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The ABCS Program for the Analysis of Echo Sounder Returns for ...

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DSTO-GD-0215Appendix 2: Geometric Errors when Converting to aReference Seafloor DepthConsider a ping <strong>of</strong> duration ∆t coming from an omnidirectional source. Thisenergy will radiate out from <strong>the</strong> source hitting <strong>the</strong> seafloor, and some <strong>of</strong> <strong>the</strong> energy will<strong>the</strong>n be backscattered back to <strong>the</strong> hydrophone. Since <strong>the</strong> energy emitted from <strong>the</strong>source will be spherical in shape and only ∆t in duration, some <strong>of</strong> <strong>the</strong> beam will firstinsonify a circle on <strong>the</strong> seafloor. <strong>The</strong> circle will widen with time until <strong>the</strong> end <strong>of</strong> <strong>the</strong>ping reaches <strong>the</strong> seafloor. <strong>The</strong>n an insonified annulus will <strong>for</strong>m on <strong>the</strong> seafloor, whichwill move out radially from <strong>the</strong> centre.To show how <strong>the</strong> geometric errors occur, consider an insonified annulus on <strong>the</strong>seafloor with a reference seafloor depth <strong>of</strong> 50 m and an actual seafloor depth <strong>of</strong> 100 mwhich is trans<strong>for</strong>med to <strong>the</strong> reference seafloor depth.Using a realistic case where <strong>the</strong> ping duration ∆t = 2 msec, θ = 30°, and <strong>the</strong> speed <strong>of</strong>sound c = 1500 m/s (see Figure 21).For <strong>the</strong> 100 m case:dSince Cosθ = 2 (eq(36) appendix 4), <strong>the</strong>re<strong>for</strong>e t=0.15396 sec at 100 m.ct2dAlso Cos( θ − ∆θ)=(eq(37) appendix 4)ct ( − ∆t)This gives ∆θ = 1.33° at 100 mdtoIf this was trans<strong>for</strong>med to <strong>the</strong> reference seafloor depth <strong>of</strong> 50 m using t' = <strong>the</strong>dtime would become t’ = 0.07698 sec, but θ and ∆θ would still be 30° and 1.33°respectfully. This gives an insonified area <strong>of</strong> 236 m 3 at <strong>the</strong> reference seafloor depth.For <strong>the</strong> 50 m case:<strong>The</strong> time t would equal 0.07698 sec, but <strong>the</strong> ping duration ∆t would still be 2 msec.Doing <strong>the</strong> above calculation again gives ∆θ = 2.76° and an insonified area <strong>of</strong> 477 m 3 .This shows that <strong>the</strong> size <strong>of</strong> <strong>the</strong> insonified annulus on <strong>the</strong> seafloor is significantlydifferent when comparing <strong>the</strong> 100 m seafloor depth adjusted to <strong>the</strong> 50 m with <strong>the</strong>reference seafloor at 50 m depth.27

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