18.10.2016 Views

UT Testing-Section 2 Physics of Ultrasound

UT Testing-Section 2 Physics of Ultrasound

UT Testing-Section 2 Physics of Ultrasound

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

However, the power or intensity <strong>of</strong> sound is generally not measured directly.<br />

Since sound consists <strong>of</strong> pressure waves, one <strong>of</strong> the easiest ways to quantify<br />

sound is to measure variations in pressure (i.e. the amplitude <strong>of</strong> the pressure<br />

wave). When making ultrasound measurements, a transducer is used, which<br />

is basically a small microphone. Transducers like most other microphones<br />

produced a voltage that is approximately proportionally to the sound pressure<br />

(P). The power carried by a traveling wave is proportional to the square <strong>of</strong> the<br />

amplitude.<br />

I α P 2 , I α V 2 where I=intensity, P=amplitude, V=voltage<br />

Therefore, the equation used to quantify a difference in sound intensity based<br />

on a measured difference in sound pressure becomes:<br />

(The factor <strong>of</strong> 2 is added to the equation because the logarithm <strong>of</strong> the square <strong>of</strong> a<br />

quantity is equal to 2 times the logarithm <strong>of</strong> the quantity.)

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!