(FINAL) Chemistry Notebook 2016-17

89
Determine the Type of Reaction for each equation.
Then predict the products of each of the following chemical reactions. If a reaction will not occur,
explain why not.
Then Balance the equation.
Double Displacement
1) __Ag2SO4 + __NaNO3 2 → _2_AgNO^3+__Na(^2)SO^4
Ag 2
(SO^4) 1
Na 1 *2= Na 2
(NO^3) 1 *2= (NO^3) 2
Ag 1 *2= Ag 2
(SO^4) 1
Na 2
(NO^3) 1 *2= (NO^3) 2
2) __NaI 2 + __CaSO4 →
Na 1 *2= Na 2
I 1 *2= I 2
Ca 1
S 1
O 4
3) __HNO3 + __Ca(OH)2 →
H 3 +1 = H 4
N 1 *2 = N 2
O 5 +3 = O 8
Ca 1
Double Displacement = __(Na^2)I+__CaI^2
Acid-Base -> _2_ H^2O+ __Ca(NO^3)^2
H 2 *2 = H 4
N 2
O 7 +1 = O 8
Ca 1
Na 2
I 2
Ca 1
S 1
O 4
4) __CaCO3 →
Ca 1
C 1
O 3
Decomposition = __CaO+__CO^2
Ca 1
C 1
O 3
5) __AlCl3 + __(NH4)PO4 → Double Displacement = __Al(PO^4)+_3_(NH^4)Cl
Al 1
Cl 3
NH^4 3
PO^4 1
^3
Al 1
Cl 3
NH^4 3
PO^4 1
6) __Pb + __Fe(NO3)3 → Not possible due to Lead (Pb) being less reactive than Iron (Fe)
7) __C3H6 2 + __O2 9 →
C 3 *2 = C 6
H 6 *2 = H 12
O 2 *9 = O 18
Combustion= _6_H^2O+_6_CO^2
C 1 *3 = C 3 *2 = C 6
H 2 *3= H 6 *2 = H 12
O 3 +10= O 13+5 = O 18
8) __Na 2 + __CaSO4 →
Single displacement = __Ca+__(Na^2)SO^4
Na 1 *2= Na 2
Ca 1
S 1
O 4
Na 2
Ca 1
S 1
O 4