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Water and Wastewater Engineering - Sciences Club

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SECONDARY TREATMENT BY SUSPENDED GROWTH BIOLOGICAL PROCESSES 23-93<br />

2. The steps in this problem (Examples 23-17 through 23-20) were provided as an illustration<br />

of the computations that can be performed without simulation modeling. Prudent<br />

design of this complex system requires the use of a simulation model to explore alternate<br />

scenarios of flow, organic composition, <strong>and</strong> loading.<br />

Example 23-21. As part of a preliminary design, estimate the required blower power for the<br />

complete-mix BOD removal <strong>and</strong> nitrification stage for Tempe’s new BPR wastewater treatment<br />

plant ( Example 23-17 ). The following estimates have been provided for the design of one of eight<br />

basins:<br />

W astewater depth � 4.5 m<br />

E q uivalent length of pipe � 105 m<br />

Air flow rate � 90 m 3 / min<br />

A mbient air pressure � 101.325 kPa � 10.333 m of H 2 O �1 atmosphere<br />

A mbient air temperature � 47 � C<br />

Steel pipe diameter � 350 mm<br />

Diffuser losses � 300 mm<br />

Allowance for clogging � 250 mm<br />

Silencer � 60 mm<br />

Air filter � 150 mm<br />

Silencer � 60 mm<br />

S ubmergence � 4,500 mm<br />

Headloss in pipe ( h L ) � 55 mm<br />

A ssume a blower efficiency of 70%.<br />

Solution:<br />

a. To size the blower, an estimate of the headloss for the steel delivery piping must be<br />

made. This is an iterative solution because the headloss is a function of pressure, <strong>and</strong> the<br />

headloss is used to determine the outlet pressure of the blower.<br />

b. Use Equation 23-66 to estimate the friction factor.<br />

0. 027<br />

3 0. 148<br />

⎛ ( 0. 350 m)<br />

f � 0. 029<br />

⎝<br />

⎜<br />

( 90 m /min)<br />

⎞ ⎛ 097 .<br />

⎠<br />

⎟ ��0. 029<br />

⎞<br />

�0.<br />

0145<br />

⎝ 195 . ⎠<br />

c. From the range of rated discharge pressures, assume a trial pressure of 50 kPa. Convert<br />

to “atmospheres” using the st<strong>and</strong>ard atmospheric pressure of 101.325 kPa.<br />

50 kPa<br />

� 049 . atm<br />

101. 325 kPa/atm<br />

This is gage pressure. Absolute pressure is 1 atm � 0.49 atm � 1.49 atm.<br />

d. The temperature correction is estimated using Equation 23-65. The ambient temperature<br />

of 47 � C must be converted to kelvins:<br />

0283 .<br />

T �( 47 �273) �<br />

149 ⎛ . atm⎞<br />

358. 23 K<br />

⎝ 10 . atm ⎠

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