19.12.2012 Views

Water and Wastewater Engineering - Sciences Club

Water and Wastewater Engineering - Sciences Club

Water and Wastewater Engineering - Sciences Club

SHOW MORE
SHOW LESS

You also want an ePaper? Increase the reach of your titles

YUMPU automatically turns print PDFs into web optimized ePapers that Google loves.

27-36 WATER AND WASTEWATER ENGINEERING<br />

O x idation of trimethylamine<br />

O x idation of acetic acid<br />

4( CH ) N �12HO⇌9CH �3CO �6HO�4NH 3 3 2 4 2 2 3<br />

CH COOH ⇌ CH � CO<br />

3 4 2<br />

(27-19)<br />

(27-20)<br />

The COD loss in anaerobic digestion is accounted for by methane production. The COD<br />

equivalent of methane is the amount of oxygen needed to oxidize methane to carbon dioxide <strong>and</strong><br />

water:<br />

CH �2O⇌ CO �2HO(27-21)<br />

4 2 2 2<br />

Thus, the COD per mole of methane is 2(32 g O 2 / mole) � 64 g O 2 / mole CH 4 .<br />

The ideal gas law provides a method of estimating the volume of methane production for a given<br />

sludge bsCOD. At st<strong>and</strong>ard conditions (0 � C <strong>and</strong> 1 atm) the volume of methane is 22.414 L/mole.<br />

The volume of CH 4 equivalent of COD converted under anaerobic conditions is<br />

22. 414 L/mole<br />

� 0. 35 L/g COD<br />

64 g mole<br />

(27-22)<br />

CO 2 is also produced in substantial amounts in the anaerobic degradation process. Typically, this<br />

is estimated as 35 percent of the gas production.<br />

Example 27-5 illustrates the method of estimating the gas production from the COD oxidized.<br />

Example 27-5. Determine the daily volume of methane <strong>and</strong> total gas produced in an anaerobic<br />

digester that is operated at 35 � C under the following conditions: biosolids flow � 300 m 3 / d;<br />

bsCOD � 5,000 g/m 3 . Assume Y � 0.04 g VSS/g COD <strong>and</strong> 95% bsCOD removal.<br />

Solution:<br />

a. Use a steady-state mass balance to determine the amount of the influent COD converted<br />

to methane:<br />

b. Determine the individual COD values.<br />

0 �CODin �CODeff �CODvss �CODCH4<br />

3 3<br />

6<br />

CODin �( 5, 000 g/m )( 300 m /d) �1.5�10 g/d<br />

6 4<br />

CODeff<br />

�( 1�0. 95)( 1. 5�10 g/d) �7. 50�10 g/d<br />

Noting from Equation 23-42 in Chapter 23, that the COD of waste activated sludge is<br />

1.42 ( P x ),<br />

CODvss � ( 142 . gCOD/gVSS)( 004 . gVSS/gCOD)<br />

( 095 . )( 1. 5 �10<br />

g/d)<br />

4<br />

�809 . �10g/d<br />

6

Hooray! Your file is uploaded and ready to be published.

Saved successfully!

Ooh no, something went wrong!