Learn to Program with C_ Learn to Program using the Popular C Programming Language ( PDFDrive )

Chapter 4 ■ Programs with Selection Logic
The following pseudocode shows how:
m = sum of meter values
cm = sum of centimeter values
if cm >= 100 then
add cm / 100 to m
set cm to cm % 100
endif
Using the above example, m is set to 5 and cm is set to 350. Since cm is greater than 100, we work
out 350 / 100 (this finds how many 100s there are in cm ) which is 3, using integer division; this
is added to m, giving 8. The next line sets cm to 350 % 100, which is 50. So the answer we get is 8m
50cm, which is correct and in the correct format.
Note that the statements in the “then part” must be written in the order shown. We must use
the (original) value of cm to work out cm / 100 before changing it in the next statement to cm % 100.
As an exercise, work out what value will be computed for the sum if these statements are reversed.
(The answer will be 5m 50cm, which is wrong. Can you see why?)
These changes are reflected in Program P4.3.
Program P4.3
//find the sum of two lengths given in meters and cm
#include <stdio.h>
int main() {
int m1, cm1, m2, cm2, mSum, cmSum;
printf("Enter values for m and cm: ");
scanf("%d %d", &m1, &cm1);
printf("Enter values for m and cm: ");
scanf("%d %d", &m2, &cm2);
mSum = m1 + m2; //add the meters
cmSum = cm1 + cm2; //add the centimeters
if (cmSum >= 100) {
mSum = mSum + cmSum / 100;
cmSum = cmSum % 100;
}
printf("\nSum is %dm %dcm\n", mSum, cmSum);
}
The following is a sample run of this program:
Enter values for m and cm: 3 150
Enter values for m and cm: 2 200
Sum is 8m 50cm
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