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Basic concepts of population genetics - Bioversity International

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… with a codominant marker<br />

Locus A<br />

Gel<br />

Indiv. 1 Indiv. 2 Indiv. 3<br />

A1 1 1 0<br />

A2 0 1 1<br />

M<br />

Genotypes<br />

A 1A 1<br />

Individuals<br />

1 2 3<br />

Scoring bands<br />

Copyright: IPGRI and Cornell University, 2003 Population <strong>genetics</strong> 22<br />

22<br />

A 1A 2<br />

Locus A<br />

A 2A 2<br />

M 1 2 3<br />

1,0 1,1 0,1<br />

(continued on next slide)<br />

With a codominant marker, the genotypes <strong>of</strong> the three genotypic classes can be<br />

observed for the two homozygotes and the heterozygote. In the drawing above, top<br />

centre, we see a gel image with the banding pattern <strong>of</strong> a codominant marker for a<br />

single locus <strong>of</strong> a diploid organism. We need to score the bands in the gel and<br />

convert them to numbers. To do so, each <strong>of</strong> the band sizes (the band in the same<br />

row) is scored and transformed to a 1 if it is present or to a 0 if it is absent. We can<br />

do it by band, as in the table at the bottom left, or by genotype, as at the bottom<br />

right corner. In the table below we can see the calculations <strong>of</strong> the expected and<br />

observed genotype frequencies, as well as the allele frequencies. (M = size<br />

marker.)<br />

Genotypes<br />

Genotype frequency<br />

(expected)<br />

Number <strong>of</strong><br />

individuals<br />

Genotype frequency<br />

(observed)<br />

A 1 A 1<br />

p 2<br />

n 11 = 40<br />

P 11 = n 11 /n<br />

= 0.20<br />

A 1 A 2<br />

2pq<br />

n 12 = 20<br />

P 12 = n 12 /n<br />

= 0.10<br />

A 2 A 2<br />

q 2<br />

n 22 = 140<br />

P 22 = n 22 /n<br />

= 0.70<br />

p = (2n 11 /2n) + (n 12 /2n) = P 11 + ½ P 12 = 0.20 + ½ (0.10) = 0.25<br />

q = (2n 22 /2n) + (n 12 /2n) = P 22 + ½ P 12 = 0.70 + ½ (0.10) = 0.75<br />

Total<br />

1<br />

n = 200<br />

1

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