Vierendeel girder and frame - Engineering Class Home Pages
Vierendeel girder and frame - Engineering Class Home Pages
Vierendeel girder and frame - Engineering Class Home Pages
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<strong>Vierendeel</strong> steel <strong>girder</strong><br />
Assume:<br />
10” tubing, allowable bending stress F b = 0.6x46 ksi F b= 27.6 ksi<br />
Girder depth d = 6’, span 10 e = 10x10’ L = 100’<br />
DL= 18 psf<br />
LL = 12 psf<br />
� = 30 psf<br />
Uniform load w = 30 psf x 20’ / 1000 w = 0.6 klf<br />
Joint load P = 0.6 x 10’ P= 6 k<br />
Max shear V = 9 P/2 = 9 x 6/2 V = 27 k<br />
CHORD BARS<br />
Shear (2 chords) V c = V/2 = 27/2 V c = 13.5 k<br />
Chord bending M c = V c e/2 = 13.5 x (10’x12”)/ 2 M c = 810 k”<br />
Moment of Inertia<br />
I = M c c/F b = 810 k” x 5”/27.6 ksi I = 147 in 4<br />
2nd bay chord shear V c = (V–P)/2 = (27-6)/2 V c = 10.5 k<br />
2nd chord bending M c = V c e/2 = 10.5 x 120”/2 M c = 630 k”<br />
WEB BAR (2nd web resists bending of 2 chords)<br />
Web bar bending M w = M c end bay + M c 2nd bay<br />
M w = 810 + 630 M w=1,440 k”<br />
Moment of Inertia<br />
I = M w c/F b = 1440 k” x 5”/27.6 ksi I = 261 in 4<br />
<strong>Vierendeel</strong> <strong>girder</strong> <strong>and</strong> <strong>frame</strong> Copyright Prof Schierle 2012 12
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