13.07.2015 Views

Momentos de inercia

Momentos de inercia

Momentos de inercia

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SoluciónEl elemento diferencial tiene un grosor <strong>de</strong> dx y <strong>de</strong> áreadA = y dx. Usando el teorema <strong>de</strong>l eje paralelo,dI xy=dI x'y'+dA { ̃x ̃y ¿( ̃x , ̃y ) localiza el centroi<strong>de</strong> <strong>de</strong>l elemento con origen el <strong>de</strong>los ejes x’, y’

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