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Diketahui :<br />
Jawab:<br />
H = 500 m<br />
Q = 60 m 3 /dtk<br />
n = 180 rpm (f = 60Hz)<br />
P = 160.000 KW<br />
D = 4400 mm<br />
Daya air instalasi PLTA<br />
P = Q ⋅ ρ ⋅ g ⋅ H = 60 x1000x9,<br />
8x500<br />
= 294000000W<br />
P = 249.000 KW<br />
Daya turbin pelton P = 200.000KW<br />
Efisiensi instalasi :<br />
`<br />
η T<br />
200000<br />
= x100<br />
= 80%<br />
249000<br />
c2<br />
Perhitungan daya dapat dihitung dengan perumusan<br />
( u c u c )<br />
P = Q.<br />
ρ . 1 1u<br />
− 2 2u<br />
karena c2 tegak lurus dengan arah u maka c2u = 0 ; u = u1 ; jadi<br />
P = Q.ρ.<br />
u1c1u<br />
dengan c1u = c1<br />
Menghitung kecepatan pancaran air dari nosel :<br />
c1 = 2gH<br />
c 1 = 2x9.<br />
8x500<br />
= 99 m/s<br />
pada efisiensi maksimum u = c 1/2<br />
u = 99/2 = 49,5 m/s<br />
P . 1 1u<br />
c1<br />
u = c1/2<br />
= Q ρ. u c = 60x1000x49,<br />
5x99<br />
= 294000000w<br />
c2<br />
c2 tegak lurus u<br />
421
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