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FGV-SP - Anglo Vestibulares

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B<br />

L<br />

L<br />

C 1<br />

C 2 R R<br />

R R<br />

Os comprimentos das chapas são:<br />

C1 = 4 ⋅ 10 = 40cm<br />

C2 = 2π ⋅R = 2π ⋅5cm = 10πcm.<br />

As áreas das chapas são:<br />

A1 = 40Lcm 2 (I)<br />

A2 = 10πLcm2 (II)<br />

Adotando π = 3,14, de (I) e (II) temos:<br />

A2<br />

10π<br />

L A2<br />

10 ⋅ 3, 14 A<br />

= ∴ = ∴ 2 = 0, 785<br />

A1<br />

40L<br />

A1<br />

40 A1<br />

∴ A2 = 78,5% A1 Portanto há uma economia de aproximadamente 21,5%.<br />

Resposta: Aproximadamente 21,5%.<br />

11<br />

GV – ADMINISTRAÇÃO/2006 ANGLO VESTIBULARES<br />

L<br />

L

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