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Foundations of Data Science

2dLYwbK

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Example <strong>of</strong> orthogonality when wavelets are <strong>of</strong> different scale.<br />

∫ ∞<br />

−∞<br />

ψ(2x)ψ(x − k)dx =<br />

Since φ(2x − 2k − j) = d−1 ∑<br />

∫ ∞<br />

−∞<br />

Since d−1 ∑<br />

j=0<br />

l=0<br />

∫ ∞<br />

∑d−1<br />

∑d−1<br />

b i φ(4x − i) b j φ(2x − 2k − j)dx<br />

−∞ i=0<br />

j=0<br />

∑d−1<br />

∑d−1<br />

∫ ∞<br />

= b i b j φ(4x − i)φ(2x − 2k − j)dx<br />

i=0<br />

i=0<br />

c l φ(4x − 4k − 2j − l)<br />

∑d−1<br />

∑d−1<br />

∑d−1<br />

∫ ∞<br />

ψ(2x)ψ(x − k)dx =<br />

b i b j c l ψ(4x − i)φ(4x − 4k − 2j − l)dx<br />

c j b j−2k = 0, d−1 ∑<br />

i=0<br />

∫ ∞<br />

−∞<br />

i=0<br />

j=0<br />

l=0<br />

−∞<br />

−∞<br />

∑d−1<br />

∑d−1<br />

∑d−1<br />

=<br />

b i b j c l δ(i − 4k − 2j − l)<br />

i=0<br />

j=0<br />

l=0<br />

∑d−1<br />

∑d−1<br />

= b i b j c i−4k−2j<br />

i=0<br />

j=0<br />

b i c i−4k−2j = δ(j − 2k) Thus<br />

∑d−1<br />

ψ(2x)ψ(x − k)dx = b j δ(j − 2k) = 0.<br />

Orthogonality <strong>of</strong> scale function with wavelet <strong>of</strong> different scale.<br />

∫ ∞<br />

−∞<br />

φ(x)ψ(2x − k)dx =<br />

∫ ∞<br />

−∞ j=0<br />

j=0<br />

∑d−1<br />

c j φ(2x − j)ψ(2x − k)dx<br />

∑d−1<br />

∫ ∞<br />

= c j φ(2x − j)ψ(2x − k)dx<br />

j=0<br />

−∞<br />

= 1 ∑d−1<br />

∫ ∞<br />

c j φ(y − j)ψ(y − k)dy<br />

2<br />

= 0<br />

j=0<br />

If ψ was <strong>of</strong> scale 2 j , φ would be expanded as a linear combination <strong>of</strong> φ <strong>of</strong> scale 2 j all <strong>of</strong><br />

which would be orthogonal to ψ.<br />

−∞<br />

369

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