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Applied Statistics Using SPSS, STATISTICA, MATLAB and R

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140 4 Parametric Tests of Hypotheses<br />

Example 4.12<br />

Q: Study the power of the tests performed in Example 4.11.<br />

A: We use the <strong>STATISTICA</strong> Power Analysis module <strong>and</strong> the descriptive<br />

statistics shown in Table 4.8.<br />

For the pair T80-T81, the st<strong>and</strong>ardised effect is Es = (39.8−37.44)/2.059 =1.1<br />

(see Table 4.7 <strong>and</strong> 4.8). It is, therefore, a large effect − justifying a high power of<br />

the test.<br />

Let us now turn our attention to the pair T80-T82, whose variables happen to<br />

have the same mean. Looking at Figure 4.12, note that in order to have a power<br />

1−β = 0.8, one must have a st<strong>and</strong>ardised effect of about Es = 0.58. Since the<br />

st<strong>and</strong>ard deviation of the paired differences is 1.68, this corresponds to a deviation<br />

of the means computed as Es × 1.68 = 0.97 ≈ 1. Thus, although the test does not<br />

reject the null hypothesis, we only have a reasonable protection against alternative<br />

hypotheses for a deviation in average maximum temperature of at least one degree<br />

centigrade.<br />

Table 4.8. Descriptive statistics of the meteorological variables used in the paired<br />

samples t test.<br />

n x s<br />

T80 25 37.44 2.20<br />

T81 25 39.80 2.74<br />

T82 25 37.44 2.29<br />

1.0<br />

.9<br />

.8<br />

.7<br />

.6<br />

.5<br />

.4<br />

.3<br />

Power<br />

.2<br />

St<strong>and</strong>ardized Effect (Es)<br />

.1<br />

0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9<br />

Figure 4.12. Power curve for the variable pair T80-T82 of Example 4.11.

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