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Technical Application Papers No.10 Photovoltaic plants - ABB

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If a voltage is applied from the outside to the PV cell in<br />

reverse direction with respect to standard operation,<br />

the produced current remains constant and the power<br />

is absorbed by the cell. When a certain value of inverse<br />

voltage (“breakdown” voltage) is exceeded, the junction<br />

P-N is perforated, as it occurs in a diode, and the current<br />

reaches a high value thus damaging the cell. In absence<br />

of light, the generated current is null for reverse voltage<br />

up to the “breakdown” voltage, then there is a discharge<br />

current similarly to the lightening conditions (Figure 2.3<br />

– left quadrant).<br />

Figure 2.3<br />

Current [A]<br />

2.3 Grid connection scheme<br />

A PV plant connected to the grid and supplying a consumer<br />

plant can be represented in a simplified way by<br />

the scheme of Figure 2.4.<br />

The supply network (assumed to be at infinite short-circuit<br />

power) is schematized by means of an ideal voltage<br />

generator the value of which is independent of the load<br />

conditions of the consumer plant. On the contrary, the<br />

PV generator is represented by an ideal current generator<br />

(with constant current and equal insolation) whereas the<br />

consumer plant by a resistance R u .<br />

Figure 2.4<br />

PV<br />

generator<br />

V inv<br />

Current [A]<br />

Ig<br />

0<br />

N<br />

Iu<br />

RU<br />

Ir<br />

U<br />

V oc<br />

Voltage [V]<br />

Network<br />

The currents I g and I r , which come from the PV generator<br />

and the network respectively, converge in the node N of<br />

Figure 2.4 and the current I u absorbed by the consumer<br />

plant comes out from the node:<br />

I u = I g + I r<br />

[2.4]<br />

Since the current on the load is also the ratio between<br />

the network voltage U and the load resistance R u :<br />

I u = U<br />

R u<br />

the relation among the currents becomes:<br />

I r = U<br />

R u<br />

I r = U<br />

R u<br />

I g = U<br />

R u<br />

- I g<br />

[2.5]<br />

[2.6]<br />

If in the [2.6] we put I g = 0, as it occurs during the night<br />

hours, the current absorbed from the grid results:<br />

[2.7]<br />

On the contrary, if all the current generated by the PV<br />

plant is absorbed by the consumer plant, the current<br />

supplied by the grid shall be null and consequently the<br />

formula [2.6] becomes:<br />

[2.8]<br />

When the insolation increases, if the generated current<br />

I g becomes higher then that required by the load I u , the<br />

current I r becomes negative, that is no more drawn from<br />

the grid but put into it.<br />

Multiplying the terms of the [2.4] by the network voltage<br />

U, the previous considerations can be made also for the<br />

powers, assuming as:<br />

• P u = U . I u = U2<br />

R u<br />

the power absorbed by the user plant;<br />

• P g = U . I g the power generated by the PV plant;<br />

• P r = U . I r the power delivered by the grid.<br />

<strong>Photovoltaic</strong> <strong>plants</strong><br />

19<br />

2 Energy production

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