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Nonlinear Control Sy.. - Free

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1.6. PHASE-PLANE ANALYSIS OF LINEAR TIME-INVARIANT SYSTEMS 11<br />

Given that T is nonsingular, its inverse, denoted T-1 exists, and we can write<br />

y = T-1ATy = Dy (1.17)<br />

Transformation of the form D = T-'AT are very well known in linear algebra, and the<br />

matrices A and D share several interesting properties:<br />

Property 1: The matrices A and D share the same eigenvalues Al and A2. For this reason<br />

the matrices A and D are said to be similar, and transformations of the form T-1AT are<br />

called similarity transformations.<br />

Property 2: Assume that the eigenvectors v1i v2 associated with the real eigenvalues A1, A2<br />

are linearly independent. In this case the matrix T defined in (1.17) can be formed by placing<br />

the eigenvectors vl and v2 as its columns. In this case we have that<br />

DAl<br />

0 A2<br />

that is, in this case the matrix A is similar to the diagonal matrix D. The importance of<br />

this transformation is that in the new coordinates y = [y1 y2]T the system is uncoupled,<br />

i.e.,<br />

[y20 '\2J [Y2<br />

or<br />

0]<br />

yl = Alyl (1.18)<br />

y2 = A2y2 (1.19)<br />

Both equations can be solved independently, and the general solution is given by (1.10).<br />

This means that the trajectories along each of the coordinate axes yl and Y2 are independent<br />

of one another.<br />

Several interesting cases can be distinguished, depending the sign of the eigenvalues<br />

Al and A2. The following examples clarify this point.<br />

Example 1.7 Consider the system<br />

[± 2]-[ 0<br />

1 -2] [x2 I .<br />

The eigenvalues in this case are Al = -1,A2 = -2. The equilibrium point of a system where<br />

both eigenvalues have the same sign is called a node. A is diagonalizable and D = T-1AT<br />

with<br />

T=[0 1 -3<br />

0<br />

1], D-[ 0 -2].<br />

- 1

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