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Nonlinear Control Sy.. - Free

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2.3. VECTOR SPACES 37<br />

Proof: First we need to show that the set of linear combinations of elements of S is a<br />

subspace of X. This is straightforward since linear combinations of linear combinations of<br />

elements of S are again linear combinations of the elements of S. Denote this subspace<br />

by N. It is immediate that N contains every element of S and thus N C M. For the<br />

converse notice that M is also a subspace which contains S, and therefore contains all<br />

linear combinations of the elements of S. Thus M C N, and the theorem is proved.<br />

2.3.3 Normed Vector Spaces<br />

As defined so far, vector spaces introduce a very useful algebraic structure by incorporating<br />

the operations of vector addition and scalar multiplication. The limitation with the concept<br />

of vector spaces is that the notion of distance associated with metric spaces has been lost.<br />

To recover this notion, we now introduce the concept of norrned vector space.<br />

Definition 2.8 A normed vector space (or simply a nonmed space) is a pair<br />

consisting of a vector space X and a norm 11 11: X -* IR such that<br />

(z) 11 x lI= 0 if and only if x = 0.<br />

(ii) 1<br />

1 Ax 111 x11 VA ER,dxEX.<br />

(iii) 11x+yj11 X 11 >-0<br />

(X,II - I<br />

thus, the norm of a vector X is nonnegative. Also, by defining property (iii), the triangle<br />

inequality,<br />

I1 x-y11=11 x-z+z-yII511x-z11+11z-y 11 dx,yEX (2.4)<br />

holds. Equation (2.4) shows that every normed linear space may be regarded as a metric<br />

space with distance defined by d(x, y) _II x - y 11.<br />

The following example introduces the most commonly used norms in the Euclidean<br />

space R.

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