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1.6. PHASE-PLANE ANALYSIS OF LINEAR TIME-INVARIANT SYSTEMS 15<br />

Figure 1.8: <strong>Sy</strong>stem trajectories for the system of Example 1.10.<br />

CASE 3: <strong>Sy</strong>stems with Complex Conjugate Eigenvalues<br />

The most interesting case occurs when the eigenvalues of the matrix A are complex conjugate,<br />

.\1,2 = a ±13. It can be shown that in this case a similarity transformation M can be<br />

found that renders the following similar matrix:<br />

M-1AM=Q=<br />

Thus the transform system has the form<br />

Q<br />

/3 a<br />

y1 = aY1 -)3Y2 (1.20)<br />

y2 = i3y1 + aye<br />

(1.21)<br />

The solution of this system of differential equations can be greatly simplified by introducing<br />

polar coordinates:<br />

P - yi + y2<br />

0 =<br />

Converting (1.20) and (1.21) to polar coordinates, we obtain<br />

which has the following solution:<br />

yl<br />

tan-1(1).<br />

p = Poe"<br />

(1.22)<br />

0 = 0o + Qt. (1.23)

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