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Métodos miméticos de pasos fraccionarios - E-Archivo - Universidad ...

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§2.3 spatial semidiscretization: a cell-no<strong>de</strong> mfd method 15<br />

⊗<br />

(i, j)<br />

(i, j + 1)<br />

⊗<br />

•<br />

( )<br />

1 1 i+ 2 , j+ 2<br />

⊗<br />

⊗<br />

(i + 1, j)<br />

(i + 1, j + 1)<br />

Figure 2.2: Stencil for the discrete divergence operator located at the (i+1/2, j+1/2)-<br />

cell center. Symbols: ⊗ : W X<br />

·,· , W Y<br />

·,·; • : (DW h )i+1/2,j+1/2.<br />

si<strong>de</strong>s of the cell:<br />

<br />

∂Ω i+1/2,j+1/2<br />

∫<br />

⟨w, n⟩ ds =<br />

ℓ β<br />

i+1/2,j<br />

∫<br />

+<br />

∫<br />

⟨w, n⟩ ds +<br />

ℓα ℓ β<br />

i+1/2,j+1<br />

∫<br />

⟨w, n⟩ ds +<br />

i+1,j+1/2<br />

ℓ α<br />

i,j+1/2<br />

⟨w, n⟩ ds<br />

⟨w, n⟩ ds.<br />

(2.13)<br />

Since each si<strong>de</strong> of the cell is a straight line, the outward unit vector normal to<br />

, we have:<br />

that si<strong>de</strong> is constant. For instance, for the si<strong>de</strong> ℓ β<br />

i+1/2,j<br />

n i+1/2,j =<br />

(<br />

yi+1,j − yi,j<br />

|ℓ β<br />

i+1/2,j |<br />

, −(xi+1,j − xi,j)<br />

|ℓ β<br />

i+1/2,j |<br />

) T<br />

.<br />

This normal vector is involved in the first integral on the right-hand si<strong>de</strong> of (2.13).<br />

Thus, we can approximate the value of such an integral by the trapezoidal rule<br />

as: ∫<br />

ℓ β<br />

⟨w, n⟩ ds ≈<br />

i+1/2,j<br />

W X i,j + W X i+1,j<br />

(yi+1,j − yi,j)<br />

2<br />

− W Y i,j + W Y i+1,j<br />

2<br />

(xi+1,j − xi,j),<br />

(2.14)<br />

where we have introduced the nodal values of the semidiscrete vector W h ∈ Hv.<br />

The integrals over the other si<strong>de</strong>s can be obtained analogously. As a result, the<br />

discrete divergence D at a mesh cell can be expressed as:<br />

(DW h ) i+1/2,j+1/2 =<br />

(W X i+1,j+1 − W X i,j )(yi,j+1 − yi+1,j) − (W X i,j+1 − W X i+1,j )(yi+1,j+1 − yi,j)<br />

2 |Ω i+1/2,j+1/2|<br />

− (W Y i+1,j+1 − W Y i,j )(xi,j+1 − xi+1,j) − (W Y i,j+1 − W Y i+1,j )(xi+1,j+1 − xi,j)<br />

,<br />

2 |Ωi+1/2,j+1/2| (2.15)

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