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Métodos miméticos de pasos fraccionarios - E-Archivo - Universidad ...

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§2.5 numerical experiments 29<br />

y<br />

1<br />

0.8<br />

0.6<br />

0.4<br />

0.2<br />

0<br />

0 0.2 0.4<br />

x<br />

0.6 0.8 1<br />

y<br />

1<br />

0.8<br />

0.6<br />

0.4<br />

0.2<br />

0<br />

0 0.2 0.4<br />

x<br />

0.6 0.8 1<br />

y<br />

1<br />

0.8<br />

0.6<br />

0.4<br />

0.2<br />

0<br />

0 0.2 0.4<br />

x<br />

0.6 0.8 1<br />

(a) N = 17 (b) N = 33 (c) N = 65<br />

Figure 2.8: Pseudo-random logically rectangular grids, for N = 17, 33, 65.<br />

In particular, if we consi<strong>de</strong>r linear problems and splittings of the form A h k =<br />

Γ h k Ah , for k = 1, 2, . . . , m, then the local time step, τk, <strong>de</strong>pends on x and is given<br />

by τk(x) = τρk(x). Un<strong>de</strong>r this interpretation, the convergence of the splitting<br />

schemes may be studied along the lines of Samarskiĭ et al. (2002).<br />

2.5. Numerical experiments<br />

This last section is <strong>de</strong>voted to the numerical testing of the proposed scheme.<br />

The reliability of the method for different types of meshes is confirmed through<br />

a set of experiments on pseudo-random and smooth grids. The numerical results<br />

show unconditional convergence of second or<strong>de</strong>r in space and first or<strong>de</strong>r in time.<br />

2.5.1. A problem on a pseudo-random grid. Let us first consi<strong>de</strong>r the semilinear<br />

parabolic problem (2.1) posed on the following space-time domain:<br />

Ω × (0, T ] = {x ≡ (x, y) ∈ R 2 : 0 < x < 1, 0 < y < 1} × (0, 1].<br />

Tensor K(x) is <strong>de</strong>fined as K(x) = RθD(x)RT θ , where Rθ is a 2 × 2 rotation<br />

matrix with angle θ = 5π and D(x) is a 2 × 2 diagonal matrix whose diagonal<br />

12<br />

entries are 1 + 2x2 + y2 and 1 + x2 + 2y2 . The nonlinear reaction term is chosen<br />

to be5 g(ψ) = 1/(1 + ψ3 ). Finally, both the source/sink term f(x, t) and the<br />

initial condition ψ0(x) are such that:<br />

ψ(x, t) = e −2π2 t sin(πx) sin(πy) (2.45)<br />

is the exact solution of the problem.<br />

The numerical solution of the previous problem follows the method of lines<br />

approach: we initially consi<strong>de</strong>r a spatial semidiscretization based on the mimetic<br />

method of Section 2.3, and then apply a linearly implicit time integrator along<br />

the lines of Section 2.4. To this end, the spatial domain Ω is discretized by<br />

5 This expression is a simplification of van Genuchten’s mo<strong>de</strong>l for root water uptake functions,<br />

commonly used in porous media applications (cf. van Genuchten (1987)).

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