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Master Dissertation

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Thus we note that the scattering matrix is in fact just the limit of the time<br />

evolution in the interaction picture. That is<br />

S = lim lim Ũ(t, s).<br />

t→∞ s→−∞<br />

If the interaction V (t) is a bounded operator we may write the unitary<br />

operator in terms of the Dyson series 3<br />

Ũ(t, s) = 1 +<br />

∞<br />

(−i) n<br />

n=1<br />

Claim. t<br />

s<br />

s<br />

s<br />

t<br />

s<br />

dt1<br />

t1<br />

s<br />

tn−1<br />

dt2 · · · dtn<br />

s<br />

˜ V (t1) · · · ˜ V (tn). (3.2)<br />

tn−1<br />

dt1 . . . dtn =<br />

s<br />

1<br />

(t − s)n<br />

n!<br />

Proof. It is obvious for n = 1.<br />

Assume it is right for n = k − 1 then<br />

t tk−1<br />

t<br />

t1 1<br />

dt1 · · · dtk = dt1<br />

(k − 1)!<br />

=<br />

This proves the claim by induction.<br />

s<br />

1<br />

(k − 1)!<br />

t<br />

1<br />

=<br />

(k − 1)!<br />

= 1<br />

(t − s)k<br />

k!<br />

s<br />

t−s<br />

0<br />

s<br />

k−1 dτ<br />

(t1 − s) k−1 dt1<br />

h k−1 dt1<br />

It follows that the sum (3.2) converges in the operator-norm since each<br />

term is bounded by<br />

t<br />

s<br />

dt1 . . .<br />

tn−1<br />

s<br />

dtn ˜ V (t1) . . . ˜ V (tn) = 1<br />

n! (t − s)n ˜ V ) n<br />

If the the interaction decreases for large times such that<br />

then the S-matrix is given by<br />

S =<br />

∞<br />

(−i) n<br />

n=0<br />

+∞<br />

−∞<br />

+∞<br />

−∞<br />

dt1<br />

which is also norm-convergent.<br />

3 See [8] page 326.<br />

t1<br />

dsV (s) < ∞,<br />

dt2 · · ·<br />

−∞<br />

21<br />

tn−1<br />

−∞<br />

dtn ˜ V (t1) · · · ˜ V (tn),

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