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Sequential Methods for Coupled Geomechanics and Multiphase Flow

Sequential Methods for Coupled Geomechanics and Multiphase Flow

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170 CHAPTER 6. COUPLED MULTIPHASE FLOW AND GEOMECHANICS<br />

where (·) k = (·) n+1,k . The subscripts J <strong>and</strong> K denote the fluid phases. Equation 6.21<br />

implies that the solutions at the k th iteration <strong>for</strong> the fully coupled or sequential methods<br />

are located near the solution of Equations 6.18 – 6.20, as illustrated in Figure 6.1.<br />

Figure 6.1: The region <strong>for</strong> the linear theory.<br />

Using Equation 6.21 <strong>and</strong> applying the fully coupled method, we can linearize Equa-<br />

tions 6.18 – 6.20, which can be written as<br />

<br />

U n+1<br />

j− 3<br />

2<br />

−( Kdr<br />

− U<br />

h<br />

n<br />

j− 3<br />

2<br />

<br />

−b (P n+1<br />

o,j−1 − P n <br />

o,j−1 −<br />

hA oo,k P<br />

f<br />

n+1<br />

o,j − P n o,j<br />

− T k o<br />

h<br />

<br />

− 2 Kdr<br />

h<br />

<br />

U n+1<br />

j− 1<br />

2<br />

<br />

P n+1<br />

o,j − P n o,j)<br />

+ hA ow,k S<br />

f<br />

n+1<br />

w,j − Sn w,j<br />

− U n<br />

j− 1<br />

<br />

+<br />

2<br />

Kdr<br />

<br />

h<br />

U n+1<br />

j+ 1<br />

2<br />

− U n<br />

j+ 1<br />

<br />

)<br />

2<br />

<br />

= 0, (6.22)<br />

+ hAo,k u<br />

∆t (−<br />

U n+1<br />

j− 1<br />

2<br />

− U n<br />

j− 1<br />

2<br />

h<br />

U n+1<br />

j+ 1<br />

2<br />

− Un j+ 1<br />

2<br />

)<br />

h<br />

+<br />

∆t<br />

∆t<br />

<br />

P n+1<br />

<br />

n+1 n+1<br />

o,j−1 − 2Po,j + Po,j+1 = 0, (6.23)<br />

hA wo,k P<br />

f<br />

n+1<br />

o,j − P n o,j<br />

− T k w<br />

h<br />

+ hA ww,k S<br />

f<br />

n+1<br />

w,j − Sn w,j<br />

+ hAw,k u<br />

(−<br />

∆t<br />

U n+1<br />

j− 1<br />

2<br />

− U n<br />

j− 1<br />

2<br />

h<br />

U n+1<br />

j+ 1<br />

2<br />

− Un j+ 1<br />

2<br />

)<br />

h<br />

+<br />

∆t<br />

∆t<br />

<br />

∆P n+1<br />

<br />

n+1 n+1<br />

o,j−1 − ∆Po,j + ∆Po,j+1 = 0, (6.24)<br />

where one iteration with the fully coupled method is required to obtain the converged

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