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Ω-Theory: Mathematics with Infinite and Infinitesimal Numbers - SELP

Ω-Theory: Mathematics with Infinite and Infinitesimal Numbers - SELP

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CHAPTER 1. Ω-CALCULUS<br />

In the same spirit, we can give a characterization of nonprincipal ultrafilters over<br />

infinite sets.<br />

Proposition 1.10.11. An ultrafilter on an infinite set A is nonprincipal if <strong>and</strong> only<br />

if it contains no finite sets, hence if <strong>and</strong> only if it contains the Frechet filter Fr(A).<br />

Proof. Let’s suppose Fr(A) ⊂ U. This implies that, for all a ∈ A, {a} c ∈ U, <strong>and</strong> so<br />

{a} ∈ U, from which we conclude that U is not principal.<br />

Now, let’s suppose that Fr(A) ⊆ U. By definition, we can find a cofinite set<br />

X ∈ U. Since U is an ultrafilter, we have that X c = {a1} ∪ . . . ∪ {ak} ∈ U <strong>and</strong> then,<br />

applying the argument of proof of Proposition 1.10.10, we conclude that {ai} ∈ U<br />

for exactly one i. We conclude that U = Uai is principal, <strong>and</strong> so the proof is<br />

concluded.<br />

It’s time to settle a result about the existence of ultrafilters. In analogy to the<br />

algebraic proof of the existence of maximal ideals, this proof is a st<strong>and</strong>ard reasoning<br />

involving Zorn’s Lemma, so we will omit some simple verifications.<br />

Proposition 1.10.12. Every filter F over a set A can be extended to an ultrafilter.<br />

Proof. Let’s consider the set<br />

G = {G filter on A : G ⊇ F}<br />

<strong>with</strong> the partial order given by inclusion.<br />

It’s straightforward to verify that every chain in G has an upper bound (just<br />

take the union of all filters in the chain <strong>and</strong> verify it’s a filter containing F). We can<br />

apply Zorn’s Lemma, that guarantees the existence of a maximal element U ∈ G.<br />

Clearly, U ⊇ F, <strong>and</strong> it’s easy to verify that U is an ultrafilter.<br />

As a consequence, we obtain the following<br />

Corollary 1.10.13. For every infinite set A, there exist a nonprincipal ultrafilters<br />

on A.<br />

Proof. Proposition 1.10.11 ensures that every ultrafilter containing the Frechet filter<br />

is nonprincipal. The existence of such ultrafilters is guaranteed by Proposition<br />

1.10.12.<br />

The importance of ultrafilters is that there’s a relation between nonprincipal<br />

maximal ideals in the ring Fun(Pfin(Ω), R) <strong>and</strong> nonprincipal ultrafilters over the<br />

set Pfin(Ω). This is a consequence of a more general fact, that we’ll show before<br />

focusing on the case of our interest. We want to warn the reader that, <strong>with</strong> abuse<br />

of notation, if ϕ ∈ Fun(A, B), we will use the notation Qϕ,c0 to denote the set<br />

{a ∈ A : ϕ(a) = 0}.<br />

Proposition 1.10.14. If Fun(A, B) <strong>with</strong> the two operations<br />

34<br />

(ϕ + ψ)(a) = ϕ(a) + ψ(a)<br />

(ϕ · ψ)(a) = ϕ(a) · ψ(a)

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