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A NULLSTELLENSATZ FOR AMOEBAS

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466 DAVID GINZBURG<br />

cuspidality of the lift. Since the computations are quite similar in all five cases, we<br />

concentrate only on the first case.<br />

Let M = Sp 2m(2n+1) .Letσ denote an irreducible cuspidal representation of<br />

Sp 2n (A). In this case, the lift is given by the integrals<br />

∫ ∫<br />

( )<br />

f (h) =<br />

ϕ σ (g)θ ɛ u(g, h) ψU (u) dudg,<br />

H 1 (F )\H 1 (A) U(F )\U(A)<br />

where H 1 = Sp 2n and h ∈ H = Sp 2(m+n) . (The group U and the character ψ U were<br />

described in Section 2.)<br />

As often happens in the constructions of liftings using small representations, the<br />

image of the lift is not always cuspidal. Usually, there is an obstruction for the lift to<br />

be cuspidal. To understand when this can happen, assume, for example, that n ≥ m.<br />

Assume that σ itself is an endoscopic lift from two cuspidal representations, from a<br />

cuspidal representation σ ′ on Sp 2(n−m) and from a cuspidal representation ɛ ′ on SO 2m .<br />

For example, if ɛ ′ = ɛ, then it is not expected that the representation π is cuspidal. In<br />

this case, there is an obstruction for the lift to be cuspidal, which is basically expressed<br />

in terms of lifts to groups of smaller rank.<br />

To simplify notation, we prove Theorem 2 only when n ≤ m. Whenn>m,<br />

the formal computations of the constant terms are similar. Since we assumed that the<br />

cuspidal representation ɛ lifts to a cuspidal representation τ(ɛ) on GL 2m , the image<br />

of the lift can fail to be cuspidal only in the case where n = m. Thus, in this case, for<br />

the image to be cuspidal we have to assume that a certain integral is zero. In our case,<br />

the integral we need to assume to be zero is given by integral (7), defined in the proof<br />

of Theorem 2. One can interpret this integral as a lift to a group of a lower rank.<br />

The proof of the cuspidality of the lift requires a manipulation of Fourier expansions<br />

performed on the automorphic functions θ ɛ . Here the function θ ɛ liesinthe<br />

space of the residue representation ɛ . At each step, one has to check that the integrals<br />

converge absolutely. These justifications are now quite standard; the main reference<br />

required is [MW, I.2.10].<br />

THEOREM 2<br />

With the above notation, let π denote the automorphic representation of Sp 2(m+n) (A)<br />

generated by the space of functions f (h) defined above. Assume that n ≤ m. Inthe<br />

case where n = m, assume also that the integral (7) is zero for every choice of data.<br />

Then π is a cuspidal representation.<br />

Proof<br />

For 1 ≤ j ≤ m + n, letV j denote the standard unipotent radical of the maximal<br />

parabolic subgroup of H whose Levi part is GL j × Sp 2(m+n−j) . Thus, we prove that

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