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242 Chapter 3 Exponential and Logarithmic Functions<br />
t 21,<br />
t 12,<br />
9. Since A 7500e rt and A 15,000 when<br />
10. Since A 1000e rt and A 2000 when we<br />
15,000 7500e 21r 2000 1000e 12r<br />
we have the following.<br />
have the following.<br />
2 e 21r<br />
ln 2 21r<br />
r ln 2<br />
21<br />
Amount after 10 years:<br />
0.033 3.3%<br />
A 7500e 0.03310 $10,432.26<br />
2 e 12r<br />
ln 2 12r<br />
r ln 2<br />
12<br />
0.058 5.8%<br />
Amount after 10 years:<br />
A 1000e 0.05810 $1786.04<br />
11. Since A 5000e rt and A 5665.74 when<br />
t 10, we have the following.<br />
5665.74 5000e 10r<br />
5665.74<br />
5000 e10r<br />
ln <br />
5665.74<br />
5000 10r<br />
The time to double is given by<br />
10,000 5000e 0.0125t<br />
2 e 0.0125t<br />
ln 2 0.0125t<br />
r 1 10 ln 5665.74<br />
5000 <br />
0.0125 1.25%<br />
t ln 2 55.5 years.<br />
0.0125<br />
12. Since A 300e rt and A 385.21 when<br />
t 10, we have the following.<br />
385.21 300e 10r<br />
385.21<br />
300 e10r<br />
ln <br />
385.21<br />
300 10r<br />
The time to double is given by<br />
600 300e 0.025t<br />
2 e 0.025t<br />
ln 2 0.025t<br />
r 1 10 ln 385.21<br />
300 <br />
0.025 2.5%<br />
t ln 2 27.7 years.<br />
0.025<br />
13. Since A Pe 0.045t and A 100,000 when t 10,<br />
we have the following.<br />
100,000 Pe 0.04510<br />
100,000<br />
e 0.45 P 63,762.82<br />
The time to double is given by<br />
127,525.64 63,762.82e 0.045t<br />
2 e 0.045t<br />
ln 2 0.045t<br />
t ln 2 15.4 years.<br />
0.045<br />
14. Since A Pe 0.02t and A 2500 when t 10, we<br />
have the following.<br />
2500 Pe 0.0210<br />
2500<br />
P $2046.83<br />
e0.02 The time to double is given by<br />
4093.66 2046.83e 0.02t<br />
2 e 0.02t<br />
ln 2 0.02t<br />
t ln 2 34.7 years.<br />
0.02<br />
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