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Solutions for certain rectangular slabs continuous over flexible ...

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SOLUTIONS FOR CERTAIN RECTANGULAR<br />

SLABS<br />

and<br />

w2 = w"' + w' <strong>for</strong> b > y > v (93)<br />

where wo and wo' represent the deflections, in their respective regions,<br />

of the infinitely long slab of span a due to the pair of concentrated<br />

loads shown in the figure, and where w' represents the deflection due<br />

to corrective moments and shears which are applied to the slab along<br />

the edges y = +b in order to produce the proper edge conditions.<br />

From the solutions given previously, one finds, where v>y> -v,<br />

Pa 2 1<br />

w'= N [(1 +av) cosh ay - ay sinh ay] e - v sin au sin ax (94)<br />

VN ,s,.. n 3<br />

and, where b > y > v,<br />

Pa 2 1<br />

w'P =-- [(l+ay) cosh av-av sinh av] e-" sin au sin ax. (95)<br />

irWN 7- n'<br />

The deflection due to the symmetrical edge corrections may be written<br />

in the <strong>for</strong>m<br />

Pa 2 1<br />

w' = - . - (b, cosh ay - cl ay sinh ay) sin au sin ax (96)<br />

where bi and ci are parameters to be determined by the boundary<br />

conditions.<br />

The boundary conditions are<br />

_- + _ -w = 0, (97)<br />

yx a 2 yb_<br />

d9z w 2 0 w 2 2<br />

8<br />

q = E2 2 - = N -- + ( 2 -M) , (98)<br />

dx 4<br />

3<br />

y=b<br />

x 2 y -b<br />

where q is the downward load on the beam and z is the downward<br />

deflection. Substitution of the derivatives obtained from (95) and<br />

(96) into (97) and (98) results in two equations in bi and Ci whose<br />

simultaneous solution gives

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