Solutions for certain rectangular slabs continuous over flexible ...

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ILLINOIS ENGINEERING EXPERIMENT STATION APPENDIX B SUMMARY OF FORMULAS FOR PARAMETRIC QUANTITIES Certain quantities have been abbreviated in the text <strong>for</strong> convenience of expression. These quantities are listed below <strong>for</strong> easy reference. n7r a nirb S= ab = -- a N= Eh* 12 (1 - U 2 ) E d lI Hi- aN ; E212 H 2 = -- ; etc. aN A = 2n7rH 2 (1 + cosh 20) + (3 + m) (1 - A) sinh 20 - 2 (1 - U)20 Ai = 2n'H 2 (cosh 2# - 1) + (3 + u) (1 = A - 4nirH 2 + 4 (1 - U)2p - u) sinh 20 + 2 (1 - A)20 Af 1 = 2nirH 2 (sinh 20 -' 20) + 4 (1 + /) + (3 + u) (1 - j) cosh 20 + (1 - 1)2 (1 + 232) Af 2 = 4 [2 cosh 0 + (1 - u) 0 sinh 3] Af 3 = 2nirH 2 sinh 20 + (1 - jA) 2 + (3 + A) (1 - 4) cosh 20 Af 4 = 4 (1 - A) cosh 0 Af 5 = 4 [2 cosh 0 cosh av + (1 - 1p) (0 sinh # cosh av - av sinh av cosh 0)]
SOLUTIONS FOR CERTAIN RECTANGULAR SLABS Afe = 2nirH 1 (sinh 2f - 20) + 8 (1 + cosh 20) Af7 = 4 (1 + cosh 20) Af 8 = (3 + y) (1 - A) sinh 20 - 2 (1 - A) 2 / Af 9 = nirH 1 [(1 + M) sinh 3 + (1 - A) 3 cosh 0] - 4 (1 - u) cosh (3 A 1 F 1 = 2n7rH 2 (sinh 2$ + 20) - 4 (1 + u) - (1 - J)2 (1 + 232) + (3 + a) (1 - j) cosh 2$ AlF2 = 4 [2 sinh 1 + (1 - ju) 0 cosh 3] AF3 = 2nrH 2 sinh 20 - (1 - M)2 + (3 + u) (1 - u) cosh 20 AF4 = 4 (1 - p) sinh 0 A 1 F, = 4 [2 sinh f sinh av + (1 - pu) (o cosh $ sinh av - av cosh av sinh 0)] AF 7 = 4 (cosh 2$ - 1) AiFs = (3 + u) (1 - u) sinh 2# + 2 (1 - jj)2 f a, = (Fs - 1) av cosh av - (F 1 - 1) sinh av bi = (f, - 1) cosh av - (fs - 1) av sinh av ci = (f 3 - 1) cosh av - 2 (1 - (lp) 2 av sinh av A 2 (1 - U)2 di = (F 3 - 1) sinh av + av cosh av A 1
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H ILL I N 0 I S UNIVERSITY OF ILLIN
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3000-5-38-14400 pEssF II
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CONTENTS (CONTINUED) V. THE RECTANG
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CONTENTS (CONCLUDED) PAGE 36. Recta
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SOLUTIONS FOR CERTAIN RECTANGULAR S
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