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Solutions for certain rectangular slabs continuous over flexible ...

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SOLUTIONS FOR CERTAIN RECTANGULAR<br />

SLABS<br />

wo, given by (219), there may then be substituted the deflection of<br />

the infinitely long slab of span b, simply supported along the edges<br />

x = + b/2, and carrying a concentrated load at the center of the span.<br />

The supports at y = ±a/2 are moved sufficiently far from the load<br />

by making a = 27rb in Equations (221) and (222).<br />

Let Moz and Mo, designate the bending moments under the load<br />

when it is at the center of the span of an infinitely long slab having<br />

simply supported edges at x = + b/2. Let Mox and MO', represent<br />

similar moments when the edges of the slab at x = + b/2 are fixed.<br />

Let Mox and Mo, represent similar moments when the slab extends a<br />

considerable distance in the directions of positive and negative x<br />

and is <strong>continuous</strong> <strong>over</strong> non-deflecting supports at x = ±b/2. Under<br />

these conditions, <strong>for</strong> Poisson's ratio p = 0.15, the moments under<br />

the load are<br />

with simply<br />

Mox = Mox<br />

supported edges M 0 o = Mox - 0.0676P<br />

! M0• = Mox - 0.0699P<br />

with fixed edges - 0.0(227)<br />

M', = Mo, - 0.03863P = Mo - 0.1063P<br />

with continuity M0' = M 0 x - 0.0293P (228)<br />

of slab M"' = Mo, - 0.01905P = Moý - 0.0867P.<br />

The numerical value of the corrections to Mo 0 and Mo, given in (228)<br />

were computed with a = 2irb in the corresponding correction functions<br />

(225). The initial quantities required in (226) may be obtained<br />

from (18) or from the numerical values and curves given by Westergaard.<br />

The corrections to Mo 0 and Moy noted in (227) were given<br />

by Westergaard* and were verified from (225) with a = 27rb and<br />

with k5 substituted <strong>for</strong> ks.<br />

It may be observed from (227) and (228) that the correction to<br />

M 0 o due to continuity of the slab is 42 per cent of the correction due<br />

to fixing the slab. Similarly it may be observed that the correction<br />

to M 0 o, due to continuity is 49 per cent of the correction due to fixing<br />

the slab. It is apparent, there<strong>for</strong>e, that the <strong>continuous</strong> slab is not,<br />

in this instance, one having a definite "percentage of fixity," but<br />

may, nevertheless, be treated as "50 per cent fixed" with a satisfactory<br />

*H. M. Westergaard, Computation of Stresses in Bridge Slabs Due to Concentrated Loads, Public<br />

Roads, V. 11, No. 1, March, 1930, p. 20; see equations 104 and 105.

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