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Alfredo Dubra's PhD thesis - Imperial College London

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6. Tear topography dynamics experiment<br />

0.25<br />

0.25<br />

0.2<br />

0.2<br />

RMS residual<br />

(mm)<br />

0.15<br />

0.1<br />

RMS (mm)<br />

0.15<br />

0.1<br />

0.05<br />

0.05<br />

0<br />

0 5 10 15 20 25<br />

time (s)<br />

0<br />

0 5 10 15 20 25<br />

time (s)<br />

Figure 6.7: Temporal evolution of the estimated wavefront error RMS (b) and residual<br />

wavefront error RMS (a) for 30 data series (around 2300 topography maps) corresponding<br />

to 19 different subjects. The blue dots correspond to the estimated RMS<br />

(b) and residual RMS (a) wavefront aberration introduced by the tear for all the 30<br />

data series. The black lines are the mean RMS at the corresponding time and the gray<br />

areas delimited by the blue lines are the areas within one standard deviation from the<br />

mean. Again, the red horizontal line indicates the diffraction limit at 632.8 nm.<br />

ever, the second moment as defined by Licznerski depends not only on the surface of<br />

the tear, but also on the intensity profile of the image, on the total intensity, on the<br />

shear amplitude, spatial coherence of the source and pupil shape. Thus, monitoring<br />

of the second order moment of the AC term (in the Fourier space) can only be used to<br />

measure relative changes within a series of interferograms from a given subject with<br />

unchanged conditions. The effect of shear amplitude, total intensity and coherence of<br />

the source could be eliminated by defining a normalised second moment,<br />

∫ ∫<br />

f 2 |AC( f)|<br />

M N =<br />

⃗ 2 d 2 f<br />

fR 2 ∫ ∫<br />

|AC( f)| ⃗ 2 d 2 f<br />

(6.6)<br />

where the integral is performed over a circle with radius f R and AC is the part of the<br />

spectrum of the interferogram centered on the carrier frequency. The moment defined<br />

in this way ranges from 0 (when the AC term is a delta function) to 1 (when the AC<br />

term is a ring of radius f R ). In practice, one has a discretised (pixelated) image, and<br />

a discrete Fourier transform, and thus the need for the discrete version of equation<br />

6.6, that is<br />

M N =<br />

∑ m 2 +n 2 ≤R 2<br />

m,n<br />

(<br />

m 2 + n 2) |AC(m, n)| 2<br />

R 2 ∑ m 2 +n 2 ≤R 2<br />

m,n<br />

|AC(m, n)| 2 (6.7)<br />

102

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