Version 5.0 The LEDA User Manual

Input and Output
void L.read(istream& I) reads a sequence of objects of type E from the input
stream I using operator ≫ (istream&, E&).
L is made a list of appropriate length and the sequence
is stored in L.
void
void
void
L.read(istream& I, char delim)
L.read(char delim = ’\n’)
L.read(string prompt, char delim = ’\n’)
as above but stops reading as soon as the first occurence
of character delim is encountered.
calls L.read(cin, delim) to read L from the standard
input stream cin.
As above, but first writes string prompt to cout.
void L.print(ostream& O, char space = ’ ’)
prints the contents of list L to the output tream O
using operator ≪ (ostream&, const E&) to print
each element. The elements are separated by character
space.
void
L.print(char space = ’ ’) calls L.print(cout, space) to print L on the standard
output stream cout.
void L.print(string header, char space = ’ ’)
Operators
As above, but first outputs string header.
list& L = const list& L1 The assignment operator makes L a copy of list
L 1 . More precisely if L 1 is the sequence of items
x 1 , x 2 , . . . , x n then L is made a sequence of items
y 1 , y 2 , . . . , y n with L[y i ] = L 1 [x i ] for 1 ≤ i ≤ n.
E& L[list item it] returns a reference to the contents of it.
list item L[int i] an abbreviation for L.get item(i).
list item L += const E& x same as L.append(x); returns the new item.
ostream&
istream&
ostream& out ≪ const list& L
same as L.print(out); returns out.
istream& in ≫ list& L
same as L.read(in)); returns in.