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Chapter 9 - XYZ Custom Plus

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9.3 The Multiplication Property of Equality<br />

533<br />

ExAmplE 4<br />

Solve for x: 2 }x<br />

4 x 5 } 8 5 15<br />

4. Solve for x: 2} }}<br />

3 4 } x 5 }6 }}<br />

5 }<br />

SOlutiOn The reciprocal of 2 }}<br />

4 5 } is 2 }5 }}<br />

4 }.<br />

2 4 } 5<br />

x 5 8 } 15<br />

− 5 — 4 1 2 4 } 5<br />

x 2<br />

5 − 5 — 4 1 8 } 15 2<br />

x 5 2 2 } 3<br />

Many times, it is convenient to divide both sides by a nonzero number to solve<br />

an equation, as the next example shows.<br />

ExAmplE 5<br />

SOlutiOn<br />

Solve for x: : 4x<br />

5 220<br />

If we divide both sides by 4, the left side will be just x, which is what<br />

we want. It is okay to divide both sides by 4 because division by 4 is equivalent to<br />

multiplication by }}<br />

1 4 } , and the multiplication property of equality states that we can<br />

multiply both sides by any number so long as it isn’t 0.<br />

4x<br />

5 220<br />

4x<br />

} 5 } 220 Divide both sides by 4<br />

4 4<br />

x 5 25<br />

Division<br />

Because 4x<br />

x means “4 times x,” the factors in the numerator of 4x<br />

x }}<br />

} are 4 and x.<br />

4<br />

Because the factor 4 is common to the numerator and the denominator, we divide<br />

it out to get just x.<br />

ExAmplE 6<br />

SOlutiOn<br />

Solve for x: 23x<br />

3 1 7 5 25<br />

We begin by adding 27 to both sides to reduce the left side to 23x<br />

3 .<br />

23x<br />

3 1 7 5 25<br />

23x<br />

3 1 7 1 (−7) 5 25 1 (−7) Add 27 to both sides<br />

23x<br />

3 5 212 Addition<br />

23x<br />

3<br />

} 5 } 212 Divide both sides by 23<br />

−3 −3<br />

5. Solve for x: : 6x<br />

5 242<br />

Note<br />

If we multiply each<br />

side by }}<br />

1 4 } , the solution<br />

looks like this:<br />

− 1 4 (4x<br />

) 5 −1<br />

4 (220)<br />

1 }1 }}<br />

4 } ? 4 2 x 5 25<br />

1x 5 25<br />

x 5 25<br />

6. Solve for x: 25x<br />

5 1 6 5 214<br />

x 5 4<br />

Division<br />

With more complicated equations we simplify each side separately before applying<br />

the addition or multiplication properties of equality. The examples below<br />

illustrate.<br />

ExAmplE 7<br />

SOlutiOn<br />

usual.<br />

Solve for x: : 5x<br />

2 8x<br />

1 3 5 4 2 10<br />

We combine similar terms to simplify each side and then solve as<br />

5x<br />

2 8x<br />

1 3 5 4 2 10<br />

23x<br />

3 1 3 5 26 Simplify each side<br />

23x<br />

3 1 3 1 (−3) 5 26 1 (−3) Add 23 to both sides<br />

23x<br />

3 5 29 Addition<br />

23x<br />

3<br />

} 5 } 29<br />

Divide both sides by 23<br />

−3 −3<br />

x 5 3<br />

Division<br />

7. Solve for x: : 3x<br />

2 7x<br />

1 5 5 3 2 18<br />

Answers<br />

4. 2 }}<br />

8 5 } 5. 27 6. 4 7. 5

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