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Proof.<br />
Identifying I ∼ = I ⊗ I, we see<br />
ϕ ◦ ϕ ′ = (ϕ ⊗ id I ) ◦ (id I ⊗ ϕ ′ ) = ϕ ⊗ ϕ ′<br />
and<br />
ϕ ′ ◦ ϕ = (id I ⊗ ϕ ′ ) ◦ (ϕ ⊗ id I ) = ϕ ⊗ ϕ ′ .<br />
✷<br />
Definition 5.1.7<br />
Let C be a pivotal category.<br />
1. Let X be an object of C and f ∈ End C (X). We define left and right traces:<br />
Tr l : End C (X) → End C (I)<br />
f ↦→ d V ◦ (id V ∗ ⊗ f) ◦ ˜b V<br />
Tr r : End C (X) → End C (I)<br />
f ↦→ ˜d V ◦ (f ⊗ id V ∗) ◦ b V<br />
(Some authors call this the quantum trace or the categorical trace.)<br />
2. One also defines left and right dimensions:<br />
dim l X := Tr l id X and dim r X := Tr r id X .<br />
Lemma 5.1.8.<br />
Both traces have the following properties:<br />
1. The traces are symmetric: for any pair of morphisms g : X → Y and f : Y → X in C, we<br />
have<br />
Tr l (gf) = Tr l (fg) and Tr r (gf) = Tr r (fg) .<br />
2. We have<br />
Tr l (f) = Tr r (f ∗ ) = Tr l (f ∗∗ )<br />
for any endomorphism f, and similar relations with left and right trace interchanged.<br />
3. Suppose that<br />
α ⊗ id X = id X ⊗ α for all α ∈ End C (I) and all objects X ∈ C . (13)<br />
Then the traces are multiplicative for the tensor product:<br />
Tr l (f ⊗ g) = Tr l (f) ∙ Tr l (g) and Tr r (f ⊗ g) = Tr r (f) ∙ Tr r (g)<br />
for all endomorphisms f, g.<br />
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