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This shows that the vectors (b i ) i=1,...N are a generating system for V and thus that V is<br />

finite-dimensional. The converse is obvious.<br />

✷<br />

Corollary 4.1.10.<br />

Let Z be a topological field theory of dimension n. Then for every closed (n − 1)-manifold M,<br />

the vector space Z(M) is finite-dimensional, and the pairing Z(M) ⊗ Z(M) → K is perfect:<br />

that is, it induces an isomorphism α from Z(M) to the dual space of Z(M).<br />

In low dimensions, it is possible to describe topological field theories very explicitly.<br />

Example 4.1.11 (Topological field theories in dimension 1).<br />

• Let Z be a 1-dimensional topological field theory. Then Z assigns a finite-dimensional<br />

vector space Z(M) to every closed oriented 0-manifold M, i.e. to a finite set of oriented<br />

points. Since the functor Z is monoidal, it suffices to know its values Z(•, +) and Z(•, −)<br />

on the positively and negatively oriented point which are finite-dimensional vector spaces<br />

dual to each other. Thus<br />

Z(M) ∼ = ( ⊗<br />

V ) ⊗ ( ⊗<br />

V ∨ )<br />

x∈M + y∈M −<br />

with V := Z(•, +).<br />

• To fully determine Z, we must also specify Z on 1-manifolds B with boundary. Since Z<br />

is a symmetric monoidal functor, it suffices to specify Z(B) when B is connected. In this<br />

case, the 1-manifold B is diffeomorphic either to a closed interval [0, 1] or to a circle S 1 .<br />

• There are five cases to consider, depending on how we interpret the one-dimensional<br />

manifold B with boundary as cobordism:<br />

(a) Suppose that B = [0, 1], regarded as a bordism from (•, +) to itself. Then Z(B)<br />

coincides with the identity map id V : V → V .<br />

(b) Suppose that B = [0, 1], regarded as a bordism from (•, −) to itself. Then Z(B)<br />

coincides with the identity map id : V ∨ → V ∨ .<br />

(c) Suppose that B = [0, 1], regarded as a bordism from (•, +) ∐ (•, −) to the empty<br />

set. Then Z(B) is a linear map from V ⊗ V ∨ into the ground field K: the evaluation<br />

map (v, λ) ↦→ λ(v). Since the order matters, we also consider the related bordism<br />

from (•, −) ∐ (•, +) to the empty set. Then Z(B) is a linear map from V ∨ ⊗ V into<br />

the ground field K: the evaluation map (λ, v) ↦→ λ(v).<br />

(d) Suppose that B = [0, 1], regarded as a bordism from the empty set to (•, +) ∐ (•, −).<br />

Then Z(B) is a linear map from K to Z((•, +) ∐ (•, −)) ∼ = V ⊗ V ∨ . Under the<br />

canonical isomorphism V ⊗V ∨ ∼ = End(V ), this linear map is given by the coevalution<br />

x ↦→ xid V . Again, we can exchange the order of the objects.<br />

(e) Suppose that B = S 1 , regarded as a bordism from the empty set to itself. Then<br />

Z(B) is a linear map from K to itself, which we can identify with an element of K.<br />

To compute this element, decompose the circle S 1 ∼ = {z ∈ C : |z| = 1} into two<br />

intervals<br />

S 1 − = {z ∈ C : (|z| = 1) ∧ Im (z) ≤ 0} S 1 + = {z ∈ C : (|z| = 1) ∧ Im (z) ≥ 0},<br />

with intersection<br />

S 1 − ∩ S 1 + = {±1} ⊆ S 1 .<br />

87

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