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field, has a larger magnitude. ANSWER: greater than the magnitude of the electric field at point B. less than the magnitude of the electric field at point B. equal to the magnitude of the electric field at point B. unknown because the value of the electric potential at point C is unknown. Problem 23.32 Description: A total electric charge of q is distributed uniformly over the surface of a metal sphere <strong>with</strong> a radius of r. The potential is zero at a point at infinity. (a) Find the value of the potential at r_1 from the center of the sphere. (b) Find the value... A total electric charge of 4.10 nC is distributed uniformly over the surface of a metal sphere <strong>with</strong> a radius of 22.0 cm . The potential is zero at a point at infinity. Part A Find the value of the potential at 53.0 cm from the center of the sphere. ANSWER: = 69.5 V Part B Find the value of the potential at 22.0 cm from the center of the sphere. ANSWER: = 168 V Part C Find the value of the potential at 11.0 cm from the center of the sphere. ANSWER: = 168 V Exercise 23.34 Description: An infinitely long line of charge has linear charge density lambda. A proton (mass m_p, charge e) is r from the line and moving directly toward the line at v. (a) Calculate the proton’s initial kinetic energy. (b) How close does the proton get to... An infinitely long line of charge has linear charge density 3.00×10 −12 C/m . A proton (mass 1.67×10 −27 kg , charge e) is 13.5 cm from the line and moving directly toward the line at 2500 m/s . Part A Calculate the proton’s initial kinetic energy. Express your answer numerically in joules to four significant figures. ANSWER:
K = = 5.219×10 −21 J Part B How close does the proton get to the line of charge? Express your answer numerically in meters to three significant figures. ANSWER: r = = 7.37×10 −2 m Problem 23.37 Description: A potential difference of V is established between parallel plates in air. (a) If the air becomes electrically conducting when the electric field exceeds E, what is the minimum separation of the plates? (b) When the separation has the minimum value... A potential difference of 5.05 kV is established between parallel plates in air. Part A If the air becomes electrically conducting when the electric field exceeds 2.90×10 6 V/m , what is the minimum separation of the plates? ANSWER: = 1.74×10 −3 m Part B When the separation has the minimum value calculated in part (a), what is the surface charge density on each plate? Use 8.85×10 −12 F/m for the permittivity of free space. ANSWER: = 2.57×10 −5 C/m 2 V(x,y,z) = Axy − B + Cy Also accepted: = 1.32×10 5 , = 9.87×10 4 Exercise 23.47 Description: In a certain region of space, the electric potential is V( (x, y, z) ) = Axy - Bx^2 + Cy, where A, B, and C are positive constants. (a) Calculate the x-component of the electric field. (b) Calculate the y-component of the electric field. (c)... In a certain region of space, the electric potential is x 2 , where A, B, and C are positive constants. Part A Calculate the x-component of the electric field. Express your answer in terms of the given quantities. ANSWER: E x =
Page 1 and 2: Signed in as Jolie Cizewski , Instr
Page 3 and 4: Part A Three equal point charges, e
Page 5: What is the work W AB done by the e
Page 9 and 10: Part A Find the potential at the po

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