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Fall 2002 - Course 3 Solutions

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Question #21<br />

Answer: B<br />

Bankrupt has 3 states 0, 1, 2, corresponding to surplus = 0, 1, 2<br />

Transition matrix is<br />

M =<br />

L<br />

NM<br />

1 0 0<br />

0. 1 0.<br />

9 0<br />

0. 01 0. 09 0.<br />

9<br />

O<br />

QP<br />

Initial vector t 0 = 0 0 1<br />

t M = t =<br />

0 1<br />

t M = t =<br />

1 2<br />

t M = t =<br />

2 3<br />

0. 01 0. 09 090 .<br />

0028 . 0162 . 081 .<br />

00523 . 0. 2187 0729 .<br />

At end of 2 months, probability ruined = 0.0285%<br />

Question #22<br />

Answer: D<br />

This is equivalent to a compound Poisson surplus process. Water from stream is like premiums.<br />

Deer arriving to drink is like claims occurring. Water drunk is like claim size.<br />

E[water drunk in a day] = (1.5)(250) = 375<br />

b1<br />

g<br />

+ θ =<br />

500<br />

375<br />

Prob(surplus level at time t is less than initial surplus, for some t)<br />

1 375<br />

= Ψb0g<br />

= = = 75%<br />

1 + θ 500

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