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Fall 2002 - Course 3 Solutions

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Question #34<br />

Answer: A<br />

b g b g = + =<br />

µ τ x t<br />

0100 . 0004 . 0104 .<br />

t<br />

p<br />

b g =<br />

-0.<br />

104<br />

τ<br />

x<br />

e<br />

t<br />

Actuarial present value (APV) = APV for cause 1 + APV for cause 2.<br />

z5<br />

0<br />

z<br />

−0. 04 t −0 . 104 t 5<br />

−0. 04 t −0.<br />

104 t<br />

0<br />

z5<br />

−0.<br />

144t<br />

. , .<br />

0<br />

b g b g<br />

2000 e e 0100 . dt + 500, 000 e e 0400 . dt<br />

c b g b gh e dt<br />

= 2000 010 + 500 000 0 004<br />

e<br />

b gj<br />

2200 −<br />

= − =<br />

0 144 1 0.<br />

144 5<br />

e<br />

.<br />

7841<br />

Question #35<br />

Answer: A<br />

R = 1 − p = q<br />

x<br />

x<br />

S = 1− p × e since e<br />

0<br />

= e<br />

x<br />

b g<br />

z<br />

1<br />

1<br />

1<br />

−k − µ x + − µ x −<br />

0<br />

0<br />

So S = 0. 75R ⇒ 1− p × e = 0.<br />

75q<br />

x<br />

e<br />

e<br />

−k<br />

k<br />

−k<br />

t k dt t dt k dt<br />

= e<br />

−<br />

z<br />

z<br />

d b g i b g<br />

x<br />

q<br />

= 1−<br />

0.<br />

75<br />

p<br />

x<br />

x<br />

1<br />

0<br />

µ<br />

x<br />

b g<br />

t dt<br />

px<br />

1−<br />

qx<br />

= =<br />

1 − 0. 75q<br />

1−<br />

0.<br />

75q<br />

L<br />

NM<br />

1−qx<br />

k = ln<br />

1−0.<br />

75q<br />

x<br />

x<br />

O<br />

QP<br />

x<br />

e<br />

z<br />

−z<br />

1<br />

0<br />

k dt

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