Fall 2002 - Course 3 Solutions
Fall 2002 - Course 3 Solutions
Fall 2002 - Course 3 Solutions
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Question #32<br />
Answer: C<br />
2<br />
A x =<br />
µ<br />
µ + 2δ<br />
= 0. 25→ µ = 0.<br />
04<br />
A x =<br />
µ<br />
µ + δ<br />
= 0.<br />
4<br />
dIAi = ¥<br />
A ds<br />
x z0 s x<br />
z<br />
∞<br />
0<br />
s x x<br />
E A ds<br />
d<br />
= ¥ -0.<br />
1s<br />
e<br />
z0<br />
=<br />
F e<br />
b0.<br />
4g HG<br />
ib04<br />
. g ds<br />
-0.<br />
1s<br />
-<br />
01 .<br />
I<br />
¥<br />
04 .<br />
= = 4<br />
KJ<br />
01 .<br />
0<br />
Alternatively, using a more fundamental formula but requiring more difficult integration.<br />
c h<br />
IA = t p µ t e dt<br />
x 0<br />
t x x<br />
=<br />
z<br />
z<br />
¥<br />
¥<br />
0<br />
= 0.<br />
04<br />
t e 0.<br />
04 e dt<br />
t e<br />
b g<br />
b<br />
-δ<br />
t<br />
-0. 04t<br />
-0.<br />
06t<br />
z¥<br />
0<br />
-0.<br />
1t<br />
dt<br />
(integration by parts, not shown)<br />
F -t<br />
1<br />
=<br />
HG -<br />
I -0.<br />
1 t<br />
¥<br />
004 . 01 K J e<br />
. 001 .<br />
0<br />
0.<br />
04<br />
= = 4<br />
0.<br />
01<br />
g
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