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Fall 2002 - Course 3 Solutions

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Question #23<br />

Answer: C<br />

Time of first claim is T 1 = − 1/ 3log 05 . = 023 .<br />

0.<br />

23<br />

b g . Size of claim = =<br />

Time of second claim is T 2 = 0. 23− 1/ 3log 0. 2 = 0.<br />

77<br />

Time of third claim is T 3 = 077 . − 1/ 3log 01 . = 1.<br />

54<br />

10 1.<br />

7<br />

0.<br />

77<br />

b g . Size of claim = =<br />

1.<br />

54<br />

b g . Size of claim = =<br />

Since initial surplus = 5> first claim, the first claim does not determine c<br />

0 z.<br />

77<br />

4<br />

Test at T 2 : Cumulative assets = 5 + ct dt = 5 + 0 . 054c<br />

Cumulative claims = 1.7 + 5.9 = 7.6<br />

Assets ≥ claims for c ≥ 4815 .<br />

Test at T 3 : Cumulative claims = 1.7 + 5.9 + 34.7 = 42.3<br />

Cumulative assets = 5+ ct dt = 5+<br />

1732 . c<br />

0<br />

z. 154<br />

0<br />

Assets ≥ claims for c ≥ 2154 .<br />

If c < 4815 . , insolvent at T 2 .<br />

If c > 4815 . , solvent throughout.<br />

49 is smallest choice > 48.15.<br />

4<br />

10 5.<br />

9<br />

10 34.<br />

7<br />

Question #24<br />

Answer: C<br />

µ xy = µ x + µ y = 014 .<br />

µ<br />

Ax<br />

= Ay<br />

=<br />

+ = 007 .<br />

= 05833 .<br />

µ δ 007 . + 005 .<br />

µ xy<br />

Axy<br />

=<br />

axy<br />

+ = 0.<br />

14 014 .<br />

1<br />

= = 0 7368 =<br />

µ δ 0 14 + 0 05 019<br />

µ + δ<br />

= 1<br />

. and<br />

. . .<br />

014 . + 0.<br />

05<br />

xy<br />

P<br />

A xy A + A − A<br />

= =<br />

a a<br />

xy<br />

x y xy<br />

xy<br />

b g<br />

2 0. 5833 −0.<br />

7368<br />

=<br />

= 0.<br />

0817<br />

52632 .<br />

xy<br />

= 5.<br />

2632

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