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Asymptotic Methods in Statistical Inference - Statistics Centre

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141<br />

Under , ( + ) = () ∼ (0 1) with<br />

mean 12 and variance 112. Thus under the hypothesis,<br />

√ 3( − 12) → (0 1) <br />

In any event, the theorem gives that<br />

√ ( − )<br />

q<br />

4[ 1 ( 1 )]<br />

and<br />

− []<br />

q[] both → (0 1)<br />

Here one can replace √ ( − )by √ ( − )<br />

(s<strong>in</strong>ce √ ( − ) = √ + ³ ´<br />

<br />

2 = ( −12 )) or<br />

by √ ( − []) (s<strong>in</strong>ce √ ( [] − )=( −12 )).<br />

Also one can replace 4[ 1 ( 1 )] = lim [ √ ]<br />

by [ √ ], s<strong>in</strong>ce (check!) []<br />

[] → 1.<br />

Thus<br />

√<br />

( − )<br />

q<br />

4[ 1 ( 1 )]<br />

and<br />

− []<br />

q[] both → (0 1)

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