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THE SOLUTION OF COUPLED MODIFIED KDV SYSTEM BY THE ...

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124 TWMS JOUR. PURE APPL. MATH., V.3, N.1, 2012<br />

Thus<br />

where<br />

ϕ(x, t; p) = ϕ(x, t; 0) +<br />

ψ(x, t; p) = ψ(x, t; 0) +<br />

∞∑<br />

m=1<br />

∞∑<br />

m=1<br />

φ(x, t; p) = u 0 (x, t) +<br />

ϕ(x, t; p) = v 0 (x, t) +<br />

ψ(x, t; p) = z 0 (x, t) +<br />

p m ∂ m ϕ(x, t; p)<br />

m! ∂p m | p=0 ,<br />

p m ∂ m ψ(x, t; p)<br />

m! ∂p m | p=0 .<br />

∞∑<br />

u m (x, t)p m , (6)<br />

m=1<br />

∞∑<br />

v m (x, t)p m , (7)<br />

m=1<br />

∞∑<br />

z m (x, t)p m , (8)<br />

m=1<br />

u m (x, t) = 1 ∂ m φ(x, t; p)<br />

m! ∂p m | p=0 , (9)<br />

v m (x, t) = 1 ∂ m ϕ(x, t; p)<br />

m! ∂p m | p=0 , (10)<br />

z m (x, t) = 1 ∂ m ψ(x, t; p)<br />

m! ∂p m | p=0 . (11)<br />

According to [4], the suitable choice of the initial condition u 0 (x, t), v 0 (x, t) and z 0 (x, t), the<br />

auxiliary linear parameter L u , L v and L z , the non-zero auxiliary parameter and the auxiliary<br />

function H 1 (x, t), H 2 (x, t) and H 3 (x, t) will guarantee that<br />

(1) The solution φ(x, t; p), ϕ(x, t; p) ψ(x, t; p) of the zero-order deformation equation (3)-(5)<br />

exists for all p ∈ [0, 1].<br />

(2) The deformation derivative ∂m φ(x, t; p)<br />

∂p m | p=0 , ∂m ϕ(x, t; p)<br />

∂p m | p=0 and ∂m ψ(x, t; p)<br />

∂p m | p=0 exists<br />

for m = 1, 2, . . . .<br />

(3) The power series (6)-(8) converges at p = 1.<br />

If p = 1<br />

φ(x, t; 1) = u(x, t) = u 0 (x, t) +<br />

ϕ(x, t; 1) = v(x, t) = v 0 (x, t) +<br />

ψ(x, t; 1) = z(x, t) = z 0 (x, t) +<br />

∞∑<br />

u m (x, t), (12)<br />

m=1<br />

∞∑<br />

v m (x, t), (13)<br />

m=1<br />

∞∑<br />

z m (x, t), (14)<br />

which must be one of the solutions of new coupled MKdV system (1). According to the definition<br />

(9)-(11), the governing equations can be deduced from the (zero-order deformation) equations<br />

(3)-(5). For further analysis, the vectors<br />

m=1<br />

⃗u n (x, t) = {u 0 (x, t), u 1 (x, t), . . . , u n (x, t)},<br />

⃗v n (x, t) = {v 0 (x, t), v 1 (x, t), . . . , v n (x, t)},<br />

⃗z n (x, t) = {z 0 (x, t), z 1 (x, t), . . . , z n (x, t)},

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