SOLUTIONS MANUAL for Stochastic Modeling: Analysis and ...
SOLUTIONS MANUAL for Stochastic Modeling: Analysis and ...
SOLUTIONS MANUAL for Stochastic Modeling: Analysis and ...
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8. (a) Restricted to periods of the day when the arrival rate is roughly constant, a<br />
Poisson process is appropriate to represent a large number of customers acting<br />
independently.<br />
(b) Not a good approximation, since most arrivals occur during a brief period just<br />
prior to the start, <strong>and</strong> only a few be<strong>for</strong>e or after this period. There<strong>for</strong>e, arrivals<br />
do not act independently.<br />
(c) Not a good approximation if patients are scheduled. We do not have independent<br />
increments because patients are anticipated. (May be a good approximation <strong>for</strong><br />
a walk-in clinic, however.)<br />
(d) Not a good approximation because the rate of finding bugs will decrease over<br />
time.<br />
(e) Probably a good approximation since fires happen (largely) independently, <strong>and</strong><br />
there are a large number of potential customers (buildings).<br />
9. (a)<br />
c = 60 + 72 + 68 = 200 total arrivals<br />
d = 3 + 3 + 3 = 9 total hours observed<br />
̂λ = c/d ≈ 22 customers/hour<br />
35<br />
ŝe =<br />
√ ̂λ<br />
d<br />
≈ 1.6 customers/hour<br />
(b) Let Y t ≡ number of arrivals by time t, <strong>and</strong> suppose λ = 22/hour.<br />
Pr{Y 3 ≤ 56} =<br />
56 ∑<br />
j=0<br />
e −22(3) (22(3)) j<br />
j!<br />
≈ 0.12<br />
Since this probability is rather small, we might conclude that Fridays are different<br />
(have a lower arrival rate).<br />
At λ =22+ŝe = 23.6<br />
<strong>and</strong> at λ =22− ŝe = 20.4<br />
Pr{Y 3 ≤ 56} ≈0.04<br />
Pr{Y 3 ≤ 56} ≈0.29<br />
So less than or equal to 56 could be quite rare if λ =23.6. This is further evidence<br />
that Fridays could be different.