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SOLUTIONS MANUAL for Stochastic Modeling: Analysis and ...

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40 CHAPTER 5. ARRIVAL-COUNTING PROCESSES<br />

(d)<br />

Pr{Y (D)<br />

1 > 300 | Y 1 = 1200}<br />

=<br />

1200 ∑<br />

n=301<br />

( ) 1200<br />

(0.13) n (0.87) 1200−n ≈ 0<br />

n<br />

18. Let {Y (T )<br />

t ; t ≥ 0} represent arrival of trucks to the restaurant.<br />

Poisson with rate λ (T ) = 10(0.1) = 1/hour<br />

Let {Y (C)<br />

t ; t ≥ 0} represent arrival of cars to the restaurant.<br />

Poisson with rate λ (C) = 20(0.1) = 2/hour<br />

(a) Y t = Y (T )<br />

t<br />

+ Y (C)<br />

t<br />

is Poisson with rate λ = λ (T ) + λ (C) =3/hour<br />

E[Y 1 ]=λ(1) = 3 cars <strong>and</strong> trucks<br />

(b) Pr{Y 1 =0} = e −3(1) ≈ 0.05<br />

(c) Let C ≡ number of passengers in a car.<br />

E[C] =(0.3)(1) + (0.5)(2) + (0.2)(3) = 1.9<br />

Let P ≡ number of passengers arriving in 1 hour.<br />

E[P ] = E [ Y (T )<br />

1 +E[C]Y (C) ]<br />

1<br />

= 1+(1.9)2 = 4.8 passengers<br />

19. Traffic engineer’s model: {Y t ; t ≥ 0} models the number of accidents <strong>and</strong> is Poisson<br />

with rate λ = 2/week.<br />

(a)<br />

Pr{Y 2 ≥ 20} =<br />

∞∑ e −2(2) (2(2)) m<br />

m=20<br />

m!<br />

= 1−<br />

19 ∑<br />

m=0<br />

e −4 4 m<br />

≈ 1.01 × 10 −8<br />

m!

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