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Introduction to differential forms

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As an application, Green’s theorem shows that the area of D can be computed<br />

as line integral on the boundary<br />

∫ ∫ ∫<br />

dxdy = ydx<br />

D<br />

If S is a closed oriented surface in R 3 , such as the surface of a sphere, S<strong>to</strong>ke’s<br />

theorem show that any exact 2-form integrates <strong>to</strong> 0. To see this write S as the<br />

union of two surfaces S 1 and S 2 with common boundary curve C. Orient C<br />

using the right hand rule with respect <strong>to</strong> S 1 , then orientation comming from S 2<br />

goes in the opposite direction. Therefore<br />

∫ ∫ ∫ ∫ ∫ ∫ ∫ ∫ ∫ ∫<br />

dω = dω + dω = ω − ω = 0<br />

S<br />

S 1 S 2 C<br />

C<br />

In vec<strong>to</strong>r notation, S<strong>to</strong>kes’ theorem is written as<br />

∫ ∫<br />

∫<br />

∇ × F · n dS = F · ds<br />

S<br />

where F is a C 1 -vec<strong>to</strong>r field.<br />

In physics, there a two fundamental vec<strong>to</strong>r fields, the electric field E and the<br />

magnetic field B. They’re governed by Maxwell’s equations, one of which is<br />

C<br />

∇ × E = − ∂B<br />

∂t<br />

where t is time. If we integrate both sides over S, apply S<strong>to</strong>kes’ theorem and<br />

simplify, we obtain Faraday’s law of induction:<br />

∫<br />

E · ds = − ∂ ∫ ∫<br />

B · n dS<br />

C ∂t<br />

To get a sense of what this says, imagine that C is wire loop and that we are<br />

dragging a magnet through it. This action will induce an electric current; the<br />

left hand integral is precisely the induced voltage and the right side is related <strong>to</strong><br />

the strength of the magnet and the rate at which it is being dragged through.<br />

S<strong>to</strong>ke’s theorem works even if the boundary has several components. However,<br />

the inner an outer components would have opposite directions.<br />

S<br />

C<br />

C<br />

2<br />

S<br />

C<br />

1<br />

16

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