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Introduction to differential forms

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8 Exactness in R 3 and conservation of energy<br />

A C 1 1-form ω = F dx + Gdy + Hdz is called exact if there is a C 2 function<br />

(called a potential) such that ω = df. ω is called closed if dω = 0, or equivalently<br />

if<br />

F y = G x , F z = H x , G z = H y<br />

Then exact 1-<strong>forms</strong> are closed.<br />

THEOREM 8.1 If ω = F dx + Gdy + Hdz is a closed form on R 3 with C 1<br />

coefficients, then ω is exact. In fact if f(x 0 , y o , z 0 ) = ∫ ω, where C is any<br />

C<br />

piecewise C 1 curve connecting (0, 0, 0) <strong>to</strong> (x 0 , y 0 , z 0 ), then df = ω.<br />

This can be rephrased in the language of vec<strong>to</strong>r fields. If F = F i + Gj + Hk<br />

is C 1 vec<strong>to</strong>r field representing a force, then it is called conservative if there is a<br />

C 2 real valued function P , called potential energy, such that F = −∇P . The<br />

theorem implies that a force F, which is C 1 on all of R 3 , is conservative if and<br />

only if ∇ × F = 0. P (x, y, z) is just the work done by moving a particle of unit<br />

mass along a path connecting (0, 0, 0) <strong>to</strong> (x, y, z).<br />

To appreciate the importance of this concept, recall from physics that the<br />

kinetic energy of a particle of constant mass m and velocity<br />

is<br />

v = ( dx<br />

dt , dy<br />

dt , dz<br />

dt )<br />

K = 1 2 m||v||2 = 1 mv · v.<br />

2<br />

Also one of New<strong>to</strong>n’s laws says<br />

m dv<br />

dt = F<br />

If F is conservative, then we can replace it by −∇P above, move it <strong>to</strong> the other<br />

side, and then dot both sides by v <strong>to</strong> obtain<br />

mv · dv<br />

dt + v · ∇P = 0<br />

which simplifies 1 <strong>to</strong><br />

d<br />

(K + P ) = 0.<br />

dt<br />

This implies that the <strong>to</strong>tal energy K + P is constant.<br />

1 This takes a bit of work that I’m leaving as an exercise. It’s probably easier <strong>to</strong> work<br />

backwards. You’ll need the product rule for dot products and the chain rule.<br />

8

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