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Introduction to differential forms

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We are subtracting the second surface integral, since we are suppose <strong>to</strong> use the<br />

inner normal for S R . Thus ∫ ∫<br />

ω = −4πm<br />

S<br />

Incidentally, this shows that ω is not exact. Thus theorem 9.2 fails for R 3 −{0}.<br />

From here, we can easily extract an expression for the flux for several particles<br />

or even a continuous distribution of matter. If F is the force of gravity<br />

associated <strong>to</strong> some mass distribution, then for any closed surface S oriented by<br />

the outer normal, then the flux<br />

∫ ∫<br />

F · ndS<br />

S<br />

is −4π times the mass inside S. For a continuous distribution with density ρ,<br />

this is given by ∫ ∫ ∫ ρdV . Applying the divergence theorem again, in this case,<br />

yields<br />

∫ ∫ ∫<br />

(∇ · F + 4πρ)dV = 0<br />

for all regions V . Therefore<br />

17 Beyond R 3<br />

V<br />

∇ · F = −4πρ<br />

It is possible <strong>to</strong> do calculus in R n with n > 3. Here the language of <strong>differential</strong><br />

<strong>forms</strong> comes in<strong>to</strong> its own. While it would be impossible <strong>to</strong> talk about the<br />

curl of a vec<strong>to</strong>r field in, say, R 4 , the derivative of a 1-form or 2-form presents<br />

no problems; we simply apply the rules we’ve already learned. Integration<br />

over higher dimensional “surfaces” or manifolds can be defined, and there is an<br />

analogue of S<strong>to</strong>kes’ theorem in this setting.<br />

As exotic as all of this sounds, there are applications of these ideas outside<br />

of mathematics. For example, in relativity theory one needs <strong>to</strong> treat the electric<br />

E = E 1 i + E 2 j + E 3 k and magnetic fields B = B 1 i + B 2 j + B 3 k as part of a<br />

single “field” on space-time. In mathematical terms, we can take space-time <strong>to</strong><br />

be R 4 - with the fourth coordinate as time t. The electromagnetic field can be<br />

represented by a 2-form<br />

F = B 3 dx ∧ dy + B 1 dy ∧ dz + B 2 dz ∧ dx + E 1 dx ∧ dt + E 2 dy ∧ dt + E 3 dz ∧ dt<br />

If we compute dF using the analogues of the rules we’ve learned:<br />

dF = ( ∂B 3<br />

∂x dx + ∂B 3<br />

∂y dy + ∂B 3<br />

∂z dz + ∂B 3<br />

dt) ∧ dx ∧ dy + . . .<br />

∂t<br />

= ( ∂B 1<br />

∂x + ∂B 2<br />

∂y + ∂B 3<br />

∂z )dx ∧ dy ∧ dz + ( ∂E 2<br />

∂x − ∂E 1<br />

∂y + ∂B 3<br />

)dx ∧ dy ∧ dt + . . .<br />

∂t<br />

19

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