TITLE MARCH 2012 - Pakistan Academy of Sciences
TITLE MARCH 2012 - Pakistan Academy of Sciences
TITLE MARCH 2012 - Pakistan Academy of Sciences
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Inclusion Properties <strong>of</strong> p-Valent Meromorphic Functions 49<br />
Pro<strong>of</strong>. To prove the first part, let<br />
1<br />
f MS ( , A , B ; ; )<br />
and set<br />
p, q, s 1 1 1<br />
<br />
<br />
<br />
<br />
1 z p, q, s<br />
1, A1 , B1<br />
f ( z)<br />
<br />
q( z) <br />
( z U),<br />
p <br />
A B f z <br />
<br />
<br />
<br />
<br />
<br />
<br />
p, q, s<br />
1, 1, 1<br />
( )<br />
<br />
(2.1)<br />
where q is analytic in U with q (0) 1.<br />
Applying (1.10) in (2.1), we obtain<br />
<br />
<br />
<br />
<br />
<br />
1<br />
1 z p, q, s<br />
1, A1 , B1<br />
f ( z)<br />
<br />
p <br />
A B f z<br />
<br />
<br />
<br />
<br />
<br />
<br />
1<br />
<br />
p, q, s<br />
1, 1, 1<br />
( )<br />
<br />
zq( z)<br />
q( z) ( z U<br />
).<br />
( p ) q( z)<br />
p <br />
Since <br />
z <br />
p<br />
maxRe ( ) , we see that<br />
zU<br />
p<br />
(2.2)<br />
Rep qz p 0 z U.<br />
Applying Lemma 1 to (2.2), it follows that<br />
<br />
q( z) ( z)<br />
, that is f ( z) MS<br />
p, q, s( 1, A1 , B1<br />
, ; )<br />
. Moreover, by using the arguments similar to<br />
those detailed above with (1.9), we can prove the<br />
second part. Therefore the pro<strong>of</strong> is completed.<br />
Theorem 2. Let S with<br />
<br />
maxRe ( z)<br />
zU<br />
<br />
1<br />
<br />
p<br />
1 1<br />
min , A p<br />
<br />
<br />
( , 0,0 p).<br />
p<br />
p<br />
<br />
A1<br />
<br />
<br />
Then<br />
MK<br />
MK<br />
1<br />
p, q, s 1 A1 B1<br />
( , , ; ; )<br />
<br />
p, q, s 1 A1 B1<br />
( , , ; ; )<br />
<br />
p, q, s 1 A1 B1<br />
MK ( 1, , ; ; ).<br />
Pro<strong>of</strong>. Applying (1.11) and using Theorem 1, we<br />
observe that<br />
1<br />
p, q, s 1 1 1<br />
f ( z) MK ( , A , B ; ; )<br />
zf ()<br />
z 1<br />
MS p, q, s ( 1, A1 , B1<br />
; ; )<br />
p<br />
zf ()<br />
z <br />
MS p, q, s ( 1, A1 , B1<br />
; ; )<br />
p<br />
<br />
p, q, s 1 1 1<br />
f ( z) MK ( , A , B ; ; ).<br />
Also<br />
<br />
p, q, s 1 1 1<br />
f ( z) MK ( , A , B ; ; )<br />
zf ()<br />
z <br />
MS p, q, s ( 1, A1 , B1<br />
; ; )<br />
p<br />
zf ()<br />
z <br />
MS p, q, s ( 1 1, A1 , B1<br />
; ; )<br />
p<br />
<br />
p, q, s 1 1 1<br />
f ( z) MK ( 1, A , B ; ; ),<br />
which evidently proves Theorem 2.<br />
Taking<br />
1<br />
Az<br />
(z) 1 B A 1 ,<br />
1<br />
Bz<br />
in Theorem 1 and Theorem 2, we have<br />
Corollary 1. Let<br />
<br />
1<br />
1<br />
p 1<br />
1<br />
min , A p<br />
A<br />
<br />
<br />
<br />
<br />
B<br />
<br />
p p<br />
1<br />
( , A<br />
0,0 <br />
p, 1 B A 1).<br />
1<br />
Then<br />
1<br />
p, q, s 1 1 1<br />
MS ( , A , B ; ; A, B)<br />
<br />
p, q, s 1 1 1<br />
MS ( , A , B ; ; A, B)<br />
<br />
p, q, s 1 1 1<br />
MS ( 1, A , B ; ; A, B),<br />
and<br />
1<br />
p, q, s 1 1 1<br />
MK ( , A , B ; ; A, B)<br />
<br />
p, q, s 1 1 1<br />
MK ( , A , B ; ; A, B)<br />
<br />
p, q, s 1 1 1<br />
MK ( 1, A , B ; ; A, B).<br />
Next, by using Lemma 2, we obtain the following<br />
<br />
inclusion relations for the class MC p,q,s 1 ,A 1 ,<br />
B 1 ;,;,.<br />
Theorem 3. Let , S with maxRe{ ( z)}<br />
<br />
<br />
1<br />
<br />
1<br />
p<br />
p<br />
min , A p<br />
MC<br />
p<br />
1<br />
p, q, s 1 A1 B1<br />
<br />
( , , ; , ; , )<br />
<br />
p, q, s 1 A1 B1<br />
MC ( , , ; , ; , )<br />
<br />
p, q, s 1 A1 B1<br />
MC ( 1, , ; , ; , ).<br />
zU<br />
1<br />
( , A<br />
0, 0 , p).<br />
1<br />
Then