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TITLE MARCH 2012 - Pakistan Academy of Sciences

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Inclusion Properties <strong>of</strong> p-Valent Meromorphic Functions 49<br />

Pro<strong>of</strong>. To prove the first part, let<br />

1<br />

f MS ( , A , B ; ; )<br />

and set<br />

p, q, s 1 1 1<br />

<br />

<br />

<br />

<br />

1 z p, q, s<br />

1, A1 , B1<br />

f ( z)<br />

<br />

q( z) <br />

( z U),<br />

p <br />

A B f z <br />

<br />

<br />

<br />

<br />

<br />

<br />

p, q, s<br />

1, 1, 1<br />

( )<br />

<br />

(2.1)<br />

where q is analytic in U with q (0) 1.<br />

Applying (1.10) in (2.1), we obtain<br />

<br />

<br />

<br />

<br />

<br />

1<br />

1 z p, q, s<br />

1, A1 , B1<br />

f ( z)<br />

<br />

p <br />

A B f z<br />

<br />

<br />

<br />

<br />

<br />

<br />

1<br />

<br />

p, q, s<br />

1, 1, 1<br />

( )<br />

<br />

zq( z)<br />

q( z) ( z U<br />

).<br />

( p ) q( z)<br />

p <br />

Since <br />

z <br />

p<br />

maxRe ( ) , we see that<br />

zU<br />

p<br />

(2.2)<br />

Rep qz p 0 z U.<br />

Applying Lemma 1 to (2.2), it follows that<br />

<br />

q( z) ( z)<br />

, that is f ( z) MS<br />

p, q, s( 1, A1 , B1<br />

, ; )<br />

. Moreover, by using the arguments similar to<br />

those detailed above with (1.9), we can prove the<br />

second part. Therefore the pro<strong>of</strong> is completed.<br />

Theorem 2. Let S with<br />

<br />

maxRe ( z)<br />

zU<br />

<br />

1<br />

<br />

p<br />

1 1<br />

min , A p<br />

<br />

<br />

( , 0,0 p).<br />

p<br />

p<br />

<br />

A1<br />

<br />

<br />

Then<br />

MK<br />

MK<br />

1<br />

p, q, s 1 A1 B1<br />

( , , ; ; )<br />

<br />

p, q, s 1 A1 B1<br />

( , , ; ; )<br />

<br />

p, q, s 1 A1 B1<br />

MK ( 1, , ; ; ).<br />

Pro<strong>of</strong>. Applying (1.11) and using Theorem 1, we<br />

observe that<br />

1<br />

p, q, s 1 1 1<br />

f ( z) MK ( , A , B ; ; )<br />

zf ()<br />

z 1<br />

MS p, q, s ( 1, A1 , B1<br />

; ; )<br />

p<br />

zf ()<br />

z <br />

MS p, q, s ( 1, A1 , B1<br />

; ; )<br />

p<br />

<br />

p, q, s 1 1 1<br />

f ( z) MK ( , A , B ; ; ).<br />

Also<br />

<br />

p, q, s 1 1 1<br />

f ( z) MK ( , A , B ; ; )<br />

zf ()<br />

z <br />

MS p, q, s ( 1, A1 , B1<br />

; ; )<br />

p<br />

zf ()<br />

z <br />

MS p, q, s ( 1 1, A1 , B1<br />

; ; )<br />

p<br />

<br />

p, q, s 1 1 1<br />

f ( z) MK ( 1, A , B ; ; ),<br />

which evidently proves Theorem 2.<br />

Taking<br />

1<br />

Az<br />

(z) 1 B A 1 ,<br />

1<br />

Bz<br />

in Theorem 1 and Theorem 2, we have<br />

Corollary 1. Let<br />

<br />

1<br />

1<br />

p 1<br />

1<br />

min , A p<br />

A<br />

<br />

<br />

<br />

<br />

B<br />

<br />

p p<br />

1<br />

( , A<br />

0,0 <br />

p, 1 B A 1).<br />

1<br />

Then<br />

1<br />

p, q, s 1 1 1<br />

MS ( , A , B ; ; A, B)<br />

<br />

p, q, s 1 1 1<br />

MS ( , A , B ; ; A, B)<br />

<br />

p, q, s 1 1 1<br />

MS ( 1, A , B ; ; A, B),<br />

and<br />

1<br />

p, q, s 1 1 1<br />

MK ( , A , B ; ; A, B)<br />

<br />

p, q, s 1 1 1<br />

MK ( , A , B ; ; A, B)<br />

<br />

p, q, s 1 1 1<br />

MK ( 1, A , B ; ; A, B).<br />

Next, by using Lemma 2, we obtain the following<br />

<br />

inclusion relations for the class MC p,q,s 1 ,A 1 ,<br />

B 1 ;,;,.<br />

Theorem 3. Let , S with maxRe{ ( z)}<br />

<br />

<br />

1<br />

<br />

1<br />

p<br />

p<br />

min , A p<br />

MC<br />

p<br />

1<br />

p, q, s 1 A1 B1<br />

<br />

( , , ; , ; , )<br />

<br />

p, q, s 1 A1 B1<br />

MC ( , , ; , ; , )<br />

<br />

p, q, s 1 A1 B1<br />

MC ( 1, , ; , ; , ).<br />

zU<br />

1<br />

( , A<br />

0, 0 , p).<br />

1<br />

Then

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