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Introduction to Enzyme and Coenzyme Chemistry - E-Library Home

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<strong>Enzyme</strong>s are Wonderful Catalysts 49<br />

Problems<br />

(1) Rationalise the rate accelerations observed for the phenyl esters (8) <strong>and</strong> (9)<br />

in Figure 3.5 which contain tertiary amine groups. What type of catalysis is<br />

operating in this case<br />

(2) Explain why the hydrolysis of the substituted benzoic acid (A) at pH 4 is<br />

1000-fold faster than the hydrolysis of the corresponding methyl ester (B)<br />

under the same conditions.<br />

O<br />

O<br />

Ph<br />

pH 4<br />

buffer<br />

OH<br />

OH<br />

+ PhCHO<br />

CO 2 R<br />

(A) R = H<br />

(B) R = Me<br />

CO 2 R<br />

(3) (a) Incubation of compound (C) under alkaline conditions leads <strong>to</strong> a<br />

unimolecular reaction of rate constant 7:3 10 2 s 1 <strong>to</strong> give a bicyclic<br />

product – suggest a structure. Incubation of compound (D) with phenoxide<br />

(PhO ) leads <strong>to</strong> a bimolecular reaction of rate constant 10 6 m 1 s 1 . Work<br />

out the eVective concentration of phenoxide in (C) <strong>and</strong> comment on the rate<br />

acceleration observed.<br />

R<br />

O<br />

(C) R = OH<br />

(D) R = H<br />

(3) (b) Epoxide hydrolase catalyses the hydrolysis of a wide range of<br />

epoxide substrates. Its active site contains an aspartate residue which is<br />

essential for catalytic activity. Given that the enzyme is most active at pH<br />

8–9, propose two possible mechanisms for the enzymatic reaction, <strong>and</strong><br />

suggest how you might distinguish them experimentally. Comparing the<br />

k cat of 1.1 s 1 for epoxide hydrolase with the rate constant for reaction of<br />

(C) above, suggest how the enzyme might achieve its additional rate acceleration.<br />

(4) Incubation of haloalkane dehalogenase (see Figure 3.19) with substrate<br />

under multiple turnover conditions in H 18<br />

2<br />

O leads <strong>to</strong> incorporation of one<br />

a<strong>to</strong>m of 18 O in<strong>to</strong> the alcohol product. However, incubation of a large<br />

quantity of enzyme with less than one equivalent of substrate in H 18<br />

2 O<br />

revealed that the product contained no 18 O. Explain this observation.

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