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Chapter 9

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HEINS09-095-117v4.qxd 12/30/06 1:58 PM Page 97<br />

CHAPTER 9<br />

SOLUTIONS TO EXERCISES<br />

1. (a)<br />

(b)<br />

(c)<br />

(d)<br />

2. (a)<br />

(b)<br />

(c)<br />

(d)<br />

3. (a)<br />

(b)<br />

(c)<br />

(d)<br />

(e)<br />

125.0 g KNO 3 2a 1 mol<br />

101.1 g b = 0.247 mol KNO 3<br />

1 mol<br />

156 mmol NaOH2a b = 0.056 mol NaOH<br />

1000 mmol<br />

15.4 * 10 2 g (NH 4 ) 2 C 2 O 4 2a 1 mol<br />

124.1 g b = 4.4 mol (NH 4) 2 C 2 O 4<br />

The conversion is: mL sol ¡ g sol ¡ g H 2 SO 4 ¡ mol H 2 SO 4<br />

116.8 mL solution2a 1.727 g<br />

mL b ¢ 0.800 g H 2SO 4<br />

≤ a 1 mol<br />

g solution 98.09 g b = 0.237 mol H 2SO 4<br />

12.10 kg NaHCO 3 2a 1000 g ba 1 mol<br />

kg 84.01 g b = 25.0 mol NaHCO 3<br />

1 g 1 mol<br />

1525 mg ZnCl 2 2a ba<br />

1000 mg 136.3 g b = 3.85 * 10-3 mol ZnCl 2<br />

19.8 * 10 24 1 mol<br />

molecules CO 2 2¢<br />

6.022 * 10 23 molecules ≤ = 16 mol CO 2<br />

1250 mL C 2 H 5 OH2a 0.789 g<br />

mL<br />

12.55 mol Fe(OH) 3 2a 106.9 g b = 273 g Fe(OH) 3<br />

mol<br />

1125 kg CaCO 3 2a 1000 g b = 1.25 * 10 5 g CaCO<br />

kg<br />

3<br />

110.5 mol NH 3 2a 17.03 g b = 179 g NH<br />

mol<br />

3<br />

1 mol<br />

ba<br />

46.07 g b = 4.3 mol C 2H 5 OH<br />

1 mol<br />

172 mmol HCl2a<br />

1000 mmol ba36.46 g b = 2.6 g HCl<br />

mol<br />

1500.0 mL Br 2 2a 3.119 g<br />

mL b = 1559.5 g Br 2 = 1.560 * 10 3 g Br 2<br />

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