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HEINS09-095-117v4.qxd 12/30/06 1:58 PM Page 100<br />
- <strong>Chapter</strong> 9 -<br />
13. Grams of NaOH<br />
Ca(OH) 2 + Na 2 CO 3 ¡ 2 NaOH + CaCO 3<br />
The conversion is: g Ca(OH) 2 ¡ mol Ca(OH) 2 ¡ mol NaOH ¡ g NaOH<br />
1500 g Ca(OH) 2 2a 1 mol 2 mol NaOH<br />
ba ba 40.00 g b = 5 * 10 2 g NaOH<br />
74.10 g 1 mol Ca(OH) 2 mol<br />
14. Grams of Zn 3 (PO 4 ) 2<br />
3 Zn + 2 H 3 PO 4 ¡ Zn 3 (PO 4 ) 2 + 3 H 2<br />
The conversion is: g Zn ¡ mol Zn ¡ mol Zn 3 (PO 4 ) 2 ¡ g Zn 3 (PO 4 ) 2<br />
110.0 g Zn2a 1 mol<br />
65.39 g b ¢ 1 mol Zn 3(PO 4 ) 2<br />
≤ a 386.1 g b = 19.7 g Zn<br />
3 mol Zn mol<br />
3 (PO 4 ) 2<br />
15. The balanced equation is Fe 2 O 3 + 3 C ¡ 2 Fe + 3 CO<br />
The conversion is: kg Fe 2 O 3 ¡ kmol Fe 2 O 3 ¡ kmol Fe ¡ kg Fe<br />
1125 kg Fe 2 O 3 2a 1 kmol 2 kmol Fe 55.85 kg<br />
ba ba b = 87.4 kg Fe<br />
159.7 kg 1 kmol Fe 2 O 3 kmol<br />
16. The balanced equation is 3 Fe + 4 H 2 O ¡ Fe 3 O 4 + 4 H 2<br />
Calculate the grams of both H 2 O and Fe to produce 375 g Fe 3 O 4<br />
1375 g Fe 3 O 4 2¢ 1 mol<br />
231.6 g ≤ a 4 mol H 2O<br />
≤ a 18.02 g b = 117 g H<br />
1 mol Fe 3 O 4 mol<br />
2 O<br />
1375 g Fe 3 O 4 2a 1 mol 3 mol Fe<br />
b ¢ ≤ a 55.85 g b = 271 g Fe<br />
231.6 g 1 mol Fe 3 O 4 mol<br />
17. The balanced equation is 2 C 2 H 6 + 7 O 2 ¡ 4 CO 2 + 6 H 2 O<br />
(a)<br />
(b)<br />
(c)<br />
115.0 mol C 2 H 6 2¢ 7 mol O 2<br />
2 mol C 2 H 6<br />
≤ = 52.5 mol O 2<br />
18.00 g H 2 O2a 1 mol<br />
18.02 g b ¢ 4 mol CO 2<br />
6 mol H 2 O ≤ a 44.01 g b = 13.0 g CO<br />
mol<br />
2<br />
175.0 g C 2 H 6 2a 1 mol<br />
30.07 g b ¢ 4 mol CO 2<br />
≤ a 44.01 g b = 2.20 * 10 2 g CO<br />
2 mol C 2 H 6 mol<br />
2<br />
(d) 12.75 mol of H 2 O2¢ 4 mol CO 2<br />
6 mol H 2 O ≤ a 44.01 g b = 80.7 g CO<br />
mol<br />
2<br />
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