CONCENTRATING SOLUTIONS FOR A PLANAR ... - CAPDE
CONCENTRATING SOLUTIONS FOR A PLANAR ... - CAPDE
CONCENTRATING SOLUTIONS FOR A PLANAR ... - CAPDE
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|x − ξ j | ≥ ε for any j = 1, . . . , m,<br />
⎛<br />
⎞−1 m∑<br />
∣<br />
δ (<br />
⎝<br />
j ⎠<br />
(δj 2 + |x − ξ ∆U<br />
j| 2 ) 3 ξ + U p ξ<br />
2<br />
j=1<br />
)<br />
(x) ∣ (<br />
≤ Ce p 4 ( C )<br />
p )p + pe − p 2<br />
13<br />
= O(pe − p 4 ), (2.21)<br />
and, if |x − ξ i | ≤ ε for some i = 1, . . . , m,<br />
|∆U ξ + U p ξ | = ∣ (<br />
1<br />
8<br />
γδi 2 2<br />
−<br />
µ<br />
p−1 (1 + |y| 2 ) 2 + 1 p ˜f 0 (y) + 1 p ˜f 2 1 (y) (2.22)<br />
i<br />
− 1 8<br />
p (1 + |y| 2 ) 2 w 0(y) − 1 )<br />
8<br />
p 2 (1 + |y| 2 ) 2 w 1(y)<br />
+U p ξ (δ iy + ξ i ) + O(pe − p 2 )<br />
∣ ∣ ,<br />
where we denote y = x−ξ i<br />
δ i<br />
. By (2.14) we deduce that, for x = δ i y + ξ i<br />
(<br />
U p ξ (x) = ( p<br />
2<br />
) p 1 + 1<br />
p−1 p v ∞(y) + 1 p<br />
γµ<br />
2 w 0(y) + 1 p p ) p<br />
p 3 w 1(y) + O( e− 4<br />
p |y| + e− 4<br />
p ) .<br />
Since (<br />
i<br />
p<br />
2<br />
p−1<br />
γµ i<br />
U p ξ (x) = 1<br />
) p =<br />
1<br />
2 , by (2.10) we get for |x − ξ i | ≤ ε √ δ i<br />
γδi 2µ p−1<br />
i<br />
(<br />
γδ 2 i µ 2<br />
p−1<br />
i<br />
8<br />
(1 + |y| 2 ) 2 [1 + 1 p<br />
w 0 (y) − 1 )<br />
8<br />
2 log2 (<br />
(1 + |y| 2 ) 2 )<br />
+ 1 8<br />
(w<br />
p 2 1 − log(<br />
(1 + |y| 2 ) 2 )w 0 + 1 8<br />
3 log3 (<br />
(1 + |y| 2 ) 2 )<br />
+ w2 0<br />
2 + 1 8<br />
8 log4 (<br />
(1 + |y| 2 ) 2 ) − w )<br />
0 8<br />
2 log2 (<br />
(1 + |y| 2 ) 2 )<br />
(<br />
log 6 )]<br />
(|y| + 2)<br />
+O<br />
p 3 + p 2 e − p 4 y + p 2 e − p 4 , y = x − ξ i<br />
.<br />
δ i<br />
Hence, in this region we obtain that<br />
⎛<br />
⎞−1 m∑<br />
∣<br />
δ (<br />
⎝<br />
j ⎠<br />
(δj 2 + |x − ξ ∆U<br />
j| 2 ) 3 ξ + U p ξ<br />
2<br />
j=1<br />
≤ ∣ (δ2 i + |x − ξ i| 2 ) 3 2<br />
(∆U ξ + U p )<br />
ξ<br />
(x) ∣ δ i<br />
)<br />
(x) ∣ ∣ (2.23)<br />
≤ C (<br />
γ (1 + |y|2 ) 3 1 log 6 )<br />
(|y| + 2)<br />
2 O<br />
p 3 (1 + |y| 2 ) 2 ≤ C p 4 , y = x − ξ i<br />
.<br />
δ i<br />
On the other hand, if ε √ δ i ≤ |x − ξ i | ≤ ε we have that<br />
( p<br />
)<br />
U p e<br />
ξ (x) = O 2 1<br />
γ (1 + |y| 2 ) 2 , y = x − ξ i<br />
,<br />
δ i