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CONCENTRATING SOLUTIONS FOR A PLANAR ... - CAPDE

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27<br />

and by Remark 3.2 we deduce that<br />

‖φ ξ ‖ H 1<br />

0 (Ω) = O (‖φ ξ‖ ∞ + ‖N(φ ξ )‖ ∗ + ‖R‖ ∗ ) ≤ C p 3 .<br />

The proof is now complete since φ ξ solves (4.1)-(4.4): in order to show<br />

the validity of (4.2), let us remark that p|φ ξ | → 0 in C(¯Ω) and by elliptic<br />

regularity theory p|φ ξ | → 0 in C 1 (¯Ω \ ∪ m j=1 B(ξ j, ɛ)) and so, we can proceed<br />

as in Remark 2.1 to show that U ξ + φ ξ > 0 in Ω.<br />

□<br />

Let ξ 1 , ξ 2 ∈ O ε . Since<br />

∆(φ ξ1 − φ ξ2 ) + pU p−1<br />

ξ 1<br />

(φ ξ1 − φ ξ2 ) = ((U ξ2 + φ ξ2 ) p − (U ξ1 + φ ξ2 ) p )<br />

(<br />

+ (U ξ1 + φ ξ2 ) p − (U ξ1 + φ ξ1 ) p − pU p−1<br />

)<br />

ξ 1<br />

(φ ξ2 − φ ξ1 ) + ∆(U ξ2 − U ξ1 )<br />

2∑ m∑<br />

+ (c ij (ξ 1 ) − c ij (ξ 2 )) e U j<br />

(ξ 1 )Z ij (ξ 1 )<br />

+<br />

i=1 j=1<br />

2∑ m∑<br />

i=1 j=1<br />

and by (3.2)<br />

(<br />

)<br />

c ij (ξ 2 ) e U j<br />

(ξ 1 )Z ij (ξ 1 ) − e U j<br />

(ξ 2 )Z ij (ξ 2 )<br />

(<br />

)<br />

‖ (U ξ1 + φ ξ2 ) p − (U ξ1 + φ ξ1 ) p − pU p−1<br />

ξ 1<br />

(φ ξ2 − φ ξ1 ) ‖ ∗<br />

≤ C p 2 ‖φ ξ 1<br />

− φ ξ2 ‖ ∞ ‖p(U ξ1 + O( 1 p 3 ))p−2 ‖ ∗<br />

= o( 1 p ‖φ ξ 1<br />

− φ ξ2 ‖ ∞ )<br />

uniformly in O ε , by Proposition 3.1 and (4.6) we get<br />

‖φ ξ1 − φ ξ2 ‖ ∞ ≤ Cp‖(U ξ2 + φ ξ2 ) p − (U ξ1 + φ ξ2 ) p ‖ ∗<br />

+ C 2∑ m∑<br />

p 3 ‖e U j<br />

(ξ 1 )Z ij (ξ 1 ) − e U j<br />

(ξ 2 )Z ij (ξ 2 )‖ ∗<br />

i=1 j=1<br />

+ Cp‖∆(U ξ2 − U ξ1 )‖ ∗ ,<br />

for any p ≥ p 0 and ξ 1 , ξ 2 ∈ O ε (here, ‖ · ‖ ∗ is considered with respect to ξ 1 ).<br />

Hence, for fixed p ≥ p 0 , the map ξ → φ ξ is continuous in C 0 (¯Ω) and, in view<br />

of Remark 3.2, in H0 1(Ω). Further, this map is a C1 -function in C 0 (¯Ω) as it<br />

follows by the Implicit Function Theorem applied to the equation:<br />

[<br />

( ) p ]<br />

G(ξ, φ) := Π ⊥ ξ U ξ + Π ⊥ ξ φ + ∆ −1 U ξ + Π ⊥ ξ φ + Π ξ φ = 0, φ ∈ C 0 (¯Ω),<br />

where Π ξ , Π ⊥ ξ<br />

are the maps from L2 (Ω) respectively onto<br />

2∑ m∑<br />

K ξ = { c ij P Z ij : c ij ∈ R for i = 1, 2, j = 1, . . . , m}<br />

i=1 j=1

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